What is the best way to restrict a Generic type within a Typescript Function Interface?

Imagine having the following interface definitions:

interface SomeInterface {a: string; b: number}
interface SomeFunction<T> {(arg: T) :T}

The usage of the function interface can be demonstrated like this:

const myFun: SomeFunction<string> = arg => arg;

An issue arises when specifying the generic type T as a string, making it less generic. The goal is to keep the type T generic while constraining it.

If we declare the SomeFunction like this:

interface SomeFunction {<T>(arg: T) : T}

it allows for generic use such as:

const myFun: SomeFunction = (arg) => arg;

However, this approach forfeits the opportunity to constrain T at the function declaration.

The objective is to have functions that implement SomeFunction specify that T must extend

SomeInterface</code and another function require <code>T
to extend something else.

This desired functionality can be achieved with declarations similar to the following:

function myFun2<T extends SomeInterface>(arg: T): T {
    console.log(arg.a);
    return arg;
}

function myFun3<T extends {c: string }>(arg: T): T {
    console.log(arg.c);
    return arg;
}

The challenge remains in these declarations not explicitly referencing the SomeFunction interface, although essentially matching its structure.

Is there an improved method to declare myFun2 and myFun3 to ensure conformity to SomeFunction?

Answer №1

To enable defining constraints at the point of call, you can generalize SomeFunction by introducing a constraint type, such as

interface SomeFunction<C> {
    <T extends C>(arg: T): T
}

and then specify the appropriate constraint when implementing your functions

const myFun2: SomeFunction<SomeInterface> = arg => {
    console.log(arg.a) // This is valid
    return arg
}

const myFun3: SomeFunction<{ c: string }> = arg => {
    console.log(arg.c) // This is valid
    return arg
}

If you wish to allow unconstrained functions, you can set a default constraint of type unknown like this

interface SomeFunction<C = unknown> {
    <T extends C>(arg: T): T
}

const unconstrained: SomeFunction = arg => arg

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