What is the best way to retrieve a specific value from an array of objects based on a condition?

Question

What is the best way to retrieve a specific value from an array of objects based on a condition?

I need some assistance with writing a function. Can you help me out?

Let's say I have an array of objects:

const movieGen = [
    { id: 28, name: "Action" }, { id: 12, name: "Adventure" }, { id: 16, name: "Animation" },
    { id: 35, name: "Comedy" }, { id: 80, name: "Crime" }, { id: 99, name: "Documentary" },
    { id: 18, name: "Drama" }, { id: 10751, name: "Family" }, { id: 14, name: "Fantasy" },
    { id: 36, name: "History" }, { id: 27, name: "Horror" }, { id: 10402, name: "Music" },
    { id: 9648, name: "Mystery" }, { id: 10749, name: "Romance" }, { id: 878, name: "Science Fiction" },
    { id: 10770, name: "TV Movie" }, { id: 53, name: "Thriller" }, { id: 10752, name: "War" },
    { id: 37, name: "Western" }
]

I am in need of a function that will return the name when provided with a matching id. For example-

const genresHandler = (id: number) => { ....//Function to be written here }

If I input 28 as the id, the function should return Action

console.log(genresHandler(28))   output should be: Action
console.log(genresHandler(12))   output should be: Adventure

Can someone assist me in creating this function using either typscript or javascript?

javascript typescript

Answer 1

Answer №1

function getGenreName(movieId) {
  const movie = movieGenres.find((movie) => movie.id === movieId);
  return movie ? movie.name : null;
}

One recommended method to search for movies within the movieGenres array is by utilizing the find function. This function takes a callback function that compares and retrieves the first movie entry which has an id matching the one passed to the getGenreName function (movieId). The output of find is then evaluated using a ternary operator, returning the movie's name if it exists, or null if it does not.

Answer 2

function getGenreName(movieId) {
  const movie = movieGenres.find((movie) => movie.id === movieId);
  return movie ? movie.name : null;
}

One recommended method to search for movies within the movieGenres array is by utilizing the find function. This function takes a callback function that compares and retrieves the first movie entry which has an id matching the one passed to the getGenreName function (movieId). The output of find is then evaluated using a ternary operator, returning the movie's name if it exists, or null if it does not.

Answer 3

Answer №2

Utilize find method to locate the object with the matching id and retrieve the corresponding name value.

The symbol ? represents a relatively recent addition in JavaScript known as optional chaining. It essentially implies that if the object is discovered, return the name; else, provide a default message.

const arr=[{id:28,name:"Action"},{id:12,name:"Adventure"},{id:16,name:"Animation"},{id:35,name:"Comedy"},{id:80,name:"Crime"},{id:99,name:"Documentary"},{id:18,name:"Drama"},{id:10751,name:"Family"},{id:14,name:"Fantasy"},{id:36,name:"History"},{id:27,name:"Horror"},{id:10402,name:"Music"},{id:9648,name:"Mystery"},{id:10749,name:"Romance"},{id:878,name:"Science Fiction"},{id:10770,name:"TV Movie"},{id:53,name:"Thriller"},{id:10752,name:"War"},{id:37,name:"Western"}];

function getGenre(arr, id) {
  return arr.find(movie => {
    return movie.id === id;
  })?.name || 'No genre found';
}

console.log(getGenre(arr, 28));
console.log(getGenre(arr, 12));
console.log(getGenre(arr, 1));

If you desire a more sophisticated approach, you could input an array of ids and obtain all the genres. You could filter out the objects where the ids array contains the movie id (returns an array of movie objects), followed by utilizing map to exclusively fetch the names from those objects.

const arr=[{id:28,name:"Action"},{id:12,name:"Adventure"},{id:16,name:"Animation"},{id:35,name:"Comedy"},{id:80,name:"Crime"},{id:99,name:"Documentary"},{id:18,name:"Drama"},{id:10751,name:"Family"},{id:14,name:"Fantasy"},{id:36,name:"History"},{id:27,name:"Horror"},{id:10402,name:"Music"},{id:9648,name:"Mystery"},{id:10749,name:"Romance"},{id:878,name:"Science Fiction"},{id:10770,name:"TV Movie"},{id:53,name:"Thriller"},{id:10752,name:"War"},{id:37,name:"Western"}];

function getGenre(arr, ids) {
  return arr
    .filter(movie => ids.includes(movie.id))
    .map(movie => movie.name);
}

console.log(getGenre(arr, [28, 12, 9648, 1]));

Answer 4

Utilize find method to locate the object with the matching id and retrieve the corresponding name value.

The symbol ? represents a relatively recent addition in JavaScript known as optional chaining. It essentially implies that if the object is discovered, return the name; else, provide a default message.

const arr=[{id:28,name:"Action"},{id:12,name:"Adventure"},{id:16,name:"Animation"},{id:35,name:"Comedy"},{id:80,name:"Crime"},{id:99,name:"Documentary"},{id:18,name:"Drama"},{id:10751,name:"Family"},{id:14,name:"Fantasy"},{id:36,name:"History"},{id:27,name:"Horror"},{id:10402,name:"Music"},{id:9648,name:"Mystery"},{id:10749,name:"Romance"},{id:878,name:"Science Fiction"},{id:10770,name:"TV Movie"},{id:53,name:"Thriller"},{id:10752,name:"War"},{id:37,name:"Western"}];

function getGenre(arr, id) {
  return arr.find(movie => {
    return movie.id === id;
  })?.name || 'No genre found';
}

console.log(getGenre(arr, 28));
console.log(getGenre(arr, 12));
console.log(getGenre(arr, 1));

If you desire a more sophisticated approach, you could input an array of ids and obtain all the genres. You could filter out the objects where the ids array contains the movie id (returns an array of movie objects), followed by utilizing map to exclusively fetch the names from those objects.

const arr=[{id:28,name:"Action"},{id:12,name:"Adventure"},{id:16,name:"Animation"},{id:35,name:"Comedy"},{id:80,name:"Crime"},{id:99,name:"Documentary"},{id:18,name:"Drama"},{id:10751,name:"Family"},{id:14,name:"Fantasy"},{id:36,name:"History"},{id:27,name:"Horror"},{id:10402,name:"Music"},{id:9648,name:"Mystery"},{id:10749,name:"Romance"},{id:878,name:"Science Fiction"},{id:10770,name:"TV Movie"},{id:53,name:"Thriller"},{id:10752,name:"War"},{id:37,name:"Western"}];

function getGenre(arr, ids) {
  return arr
    .filter(movie => ids.includes(movie.id))
    .map(movie => movie.name);
}

console.log(getGenre(arr, [28, 12, 9648, 1]));

Answer 5

Answer №3

When using JavaScript, you can create a movieGen array with different genres:

const movieGen = [
{ id: 28, name: "Action" }, { id: 12, name: "Adventure" }, { id: 16, name: "Animation" },
{ id: 35, name: "Comedy" }, { id: 80, name: "Crime" }, { id: 99, name: "Documentary" },
{ id: 18, name: "Drama" }, { id: 10751, name: "Family" }, { id: 14, name: "Fantasy" },
{ id: 36, name: "History" }, { id: 27, name: "Horror" }, { id: 10402, name: "Music" },
{ id: 9648, name: "Mystery" }, { id: 10749, name: "Romance" }, { id: 878, name: "Science Fiction" },
{ id: 10770, name: "TV Movie" }, { id: 53, name: "Thriller" }, { id: 10752, name: "War" },
{ id: 37, name: "Western" }
];

function findGenreById(id) {
  const res = movieGen.filter(element => element.id === id);
  console.log(res[0].name);
}

findGenreById(28);

Answer 6

When using JavaScript, you can create a movieGen array with different genres:

const movieGen = [
{ id: 28, name: "Action" }, { id: 12, name: "Adventure" }, { id: 16, name: "Animation" },
{ id: 35, name: "Comedy" }, { id: 80, name: "Crime" }, { id: 99, name: "Documentary" },
{ id: 18, name: "Drama" }, { id: 10751, name: "Family" }, { id: 14, name: "Fantasy" },
{ id: 36, name: "History" }, { id: 27, name: "Horror" }, { id: 10402, name: "Music" },
{ id: 9648, name: "Mystery" }, { id: 10749, name: "Romance" }, { id: 878, name: "Science Fiction" },
{ id: 10770, name: "TV Movie" }, { id: 53, name: "Thriller" }, { id: 10752, name: "War" },
{ id: 37, name: "Western" }
];

function findGenreById(id) {
  const res = movieGen.filter(element => element.id === id);
  console.log(res[0].name);
}

findGenreById(28);

Answer 7

Answer №4

Locate the target object by utilizing the find() method. Retrieve a specific property:

const movieGenres = [{id:28, name: "Action" }, {id:12,name:"Adventure"}, { id: 16, name: "Animation"}];
const handleGenres = (movieId) =>
movieGenres.find((genre) => genre.id === movieId)?.name ?? ''

console.log(handleGenres(28));
console.log(handleGenres(29));
console.log(handleGenres(12));

To manage scenarios where an item is not present, you can implement optional chaining. The optional chaining feature allows you to access nested properties of an object without needing nested if statements.

Answer 8

Locate the target object by utilizing the find() method. Retrieve a specific property:

const movieGenres = [{id:28, name: "Action" }, {id:12,name:"Adventure"}, { id: 16, name: "Animation"}];
const handleGenres = (movieId) =>
movieGenres.find((genre) => genre.id === movieId)?.name ?? ''

console.log(handleGenres(28));
console.log(handleGenres(29));
console.log(handleGenres(12));

To manage scenarios where an item is not present, you can implement optional chaining. The optional chaining feature allows you to access nested properties of an object without needing nested if statements.

Answer 9

Answer №5

function getGenreName(id) {
    const foundGenre = movieGenresArray.find(genre => genre.id === id);
    // if genre is found, return the name, otherwise return null
    return foundGenre ? foundGenre.name : null;
}

Answer 10

function getGenreName(id) {
    const foundGenre = movieGenresArray.find(genre => genre.id === id);
    // if genre is found, return the name, otherwise return null
    return foundGenre ? foundGenre.name : null;
}

Answer 11

Answer №6

const movieGenres = [
    { id: 28, name: "Action" }, { id: 12, name: "Adventure" }, { id: 16, name: "Animation" },
    { id: 35, name: "Comedy" }, { id: 80, name: "Crime" }, { id: 99, name: "Documentary" },
    { id: 18, name: "Drama" }, { id: 10751, name: "Family" }, { id: 14, name: "Fantasy" },
    { id: 36, name: "History" }, { id: 27, name: "Horror" }, { id: 10402, name: "Music" },
    { id: 9648, name: "Mystery" }, { id: 10749, name: "Romance" }, { id: 878, name: "Science Fiction" },
    { id: 10770, name: "TV Movie" }, { id: 53, name: "Thriller" }, { id: 10752, name: "War" },
    { id: 37, name: "Western" }
]

var selectedGenre = movieGenres.filter(item => item.id === parseInt(28)); // pass your value instead of 28
selectedGenre.map(matchedItem => console.log(matchedItem))

Answer 12

const movieGenres = [
    { id: 28, name: "Action" }, { id: 12, name: "Adventure" }, { id: 16, name: "Animation" },
    { id: 35, name: "Comedy" }, { id: 80, name: "Crime" }, { id: 99, name: "Documentary" },
    { id: 18, name: "Drama" }, { id: 10751, name: "Family" }, { id: 14, name: "Fantasy" },
    { id: 36, name: "History" }, { id: 27, name: "Horror" }, { id: 10402, name: "Music" },
    { id: 9648, name: "Mystery" }, { id: 10749, name: "Romance" }, { id: 878, name: "Science Fiction" },
    { id: 10770, name: "TV Movie" }, { id: 53, name: "Thriller" }, { id: 10752, name: "War" },
    { id: 37, name: "Western" }
]

var selectedGenre = movieGenres.filter(item => item.id === parseInt(28)); // pass your value instead of 28
selectedGenre.map(matchedItem => console.log(matchedItem))

What is the best way to retrieve a specific value from an array of objects based on a condition?

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

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