What is the best way to swap out the if else statement with a Ternary operator within a JavaScript function?

Question

What is the best way to swap out the if else statement with a Ternary operator within a JavaScript function?

Is there a way to replace the if else statement in the function using a Ternary operator in JavaScript?

private getProductName(productType: string): string {
    let productName = 'Product not found';

    this.deal.packages.find(p => p.isSelected).dealProducts.find(dp => (dp.children.length > 0 && dp.children[0].product.productTypeCode == productType)) ? 
      productName = this.deal.packages.find(p => p.isSelected).dealProducts.find(dp => (dp.children.length > 0 && dp.children[0].product.productTypeCode == productType)).children[0].product.name : 
    this.deal.packages.find(p => p.isSelected).dealProducts.find(dp => (dp.children.length === 0 && dp.product.productTypeCode === productType)) ?
      productName = this.deal.packages.find(p => p.isSelected).dealProducts.find(dp => (dp.children.length === 0 && dp.product.productTypeCode === productType)).product.name :
    null;

    return productName;
}

javascript typescript conditional-operator

Answer 1

Answer №1

The current code implementation suffers from inefficiency due to unnecessary redundancy in finding the same element multiple times, resulting in looping multiple times.

To improve readability and efficiency, I restructured the code into separate parts. It now loops only once over the object to identify items with children and those without children, utilizing a ternary operator to streamline this process.

Additionally, the updated code now efficiently determines whether the identified item is a child or not before retrieving the object.

// Retrieve the selected package products
var selectedPackageProducts = this.deal.packages.find(p => p.isSelected).dealProducts;

// Check if the product type belongs to the children or parent (if no children)
const selectedProduct = selectedPackageProducts.find(dp => 
    dp.children.length > 0 ? 
    dp.children[0].product.productTypeCode === productType :
    dp.product.productTypeCode === productType)

// Use children if available, otherwise refer to the parent
const productObj = selectedProduct && selectedProduct.children.length ? 
    selectedProduct.children[0] :
    selectedProduct;

// Obtain the name of the product 
const productName = productObj && productObj.product.name

Answer 2

The current code implementation suffers from inefficiency due to unnecessary redundancy in finding the same element multiple times, resulting in looping multiple times.

To improve readability and efficiency, I restructured the code into separate parts. It now loops only once over the object to identify items with children and those without children, utilizing a ternary operator to streamline this process.

Additionally, the updated code now efficiently determines whether the identified item is a child or not before retrieving the object.

// Retrieve the selected package products
var selectedPackageProducts = this.deal.packages.find(p => p.isSelected).dealProducts;

// Check if the product type belongs to the children or parent (if no children)
const selectedProduct = selectedPackageProducts.find(dp => 
    dp.children.length > 0 ? 
    dp.children[0].product.productTypeCode === productType :
    dp.product.productTypeCode === productType)

// Use children if available, otherwise refer to the parent
const productObj = selectedProduct && selectedProduct.children.length ? 
    selectedProduct.children[0] :
    selectedProduct;

// Obtain the name of the product 
const productName = productObj && productObj.product.name

Answer 3

Answer №2

Stepping into what now feels like a battlefield of conflicting opinions, I willingly put myself at risk to demonstrate two important points.

The pursuit of clean code and readability is not merely about asserting superiority or flaunting expertise. It serves the purpose of maintaining one's sanity and well-being (as well as that of the entire team), especially for those tasked with maintaining the code in the near future and beyond.
Through refactoring the original poster's code to enhance readability, several objectives are accomplished:

Eliminating redundant and unnecessary data retrievals, focusing only on the essential ones and doing so efficiently.
Clarifying the nature of the data being handled, making it easier to identify and modify during future refactorings.
Successfully meeting the OP's requirement for a return value based on nested ternary operators, a task made considerably more challenging without prior cleanup.

private retrieveProductName(productType: string): string {
  const defaultName = 'Product not found';

  const selectedPackageProducts = this.deal.packages
    .find(p => p.isSelected).dealProducts;

  const chosenProducts = selectedPackageProducts
    .find(dp => (dp.children.length > 0 && dp.children[0].product.productTypeCode === productType));

  const selectedProduct = !chosenProducts && selectedPackageProducts
    .find(dp => (dp.children.length === 0 && dp.product.productTypeCode === productType));

  return chosenProducts
    ? chosenProducts.children[0].product.name
    : (selectedProduct ? selectedProduct.product.name : defaultName);
}

Answer 4

Stepping into what now feels like a battlefield of conflicting opinions, I willingly put myself at risk to demonstrate two important points.

The pursuit of clean code and readability is not merely about asserting superiority or flaunting expertise. It serves the purpose of maintaining one's sanity and well-being (as well as that of the entire team), especially for those tasked with maintaining the code in the near future and beyond.
Through refactoring the original poster's code to enhance readability, several objectives are accomplished:

Eliminating redundant and unnecessary data retrievals, focusing only on the essential ones and doing so efficiently.
Clarifying the nature of the data being handled, making it easier to identify and modify during future refactorings.
Successfully meeting the OP's requirement for a return value based on nested ternary operators, a task made considerably more challenging without prior cleanup.

private retrieveProductName(productType: string): string {
  const defaultName = 'Product not found';

  const selectedPackageProducts = this.deal.packages
    .find(p => p.isSelected).dealProducts;

  const chosenProducts = selectedPackageProducts
    .find(dp => (dp.children.length > 0 && dp.children[0].product.productTypeCode === productType));

  const selectedProduct = !chosenProducts && selectedPackageProducts
    .find(dp => (dp.children.length === 0 && dp.product.productTypeCode === productType));

  return chosenProducts
    ? chosenProducts.children[0].product.name
    : (selectedProduct ? selectedProduct.product.name : defaultName);
}

Answer 5

Answer №3

Instead of writing the traditional syntax: IF condition THEN do_a ELSE do_b, you have the option to streamline your code using ternary operators in a similar manner.

(condition) ? do_a : do_b;

Here is a concrete example specific to your scenario:

private getProductName(productType: string): string {
    return (this.deal.packages.find(p  => p.isSelected).dealProducts.find(dp => (dp.children.length > 0 && dp.children[0].product.productTypeCode == productType)))
 ? this.deal.packages.find(p  => p.isSelected).dealProducts.find(dp => (dp.children.length > 0 && dp.children[0].product.productTypeCode == productType)).children[0].product.name
 : (this.deal.packages.find(p  => p.isSelected).dealProducts.find(dp => (dp.children.length === 0 && dp.product.productTypeCode === productType)))
 ? this.deal.packages.find(p  => p.isSelected).dealProducts.find(dp => (dp.children.length === 0 && dp.product.productTypeCode === productType)).product.name
 : 'Product not found';
}

By the way, it is advisable to consider extracting methods for do_a and do_b for better code organization.

Answer 6

Instead of writing the traditional syntax: IF condition THEN do_a ELSE do_b, you have the option to streamline your code using ternary operators in a similar manner.

(condition) ? do_a : do_b;

Here is a concrete example specific to your scenario:

private getProductName(productType: string): string {
    return (this.deal.packages.find(p  => p.isSelected).dealProducts.find(dp => (dp.children.length > 0 && dp.children[0].product.productTypeCode == productType)))
 ? this.deal.packages.find(p  => p.isSelected).dealProducts.find(dp => (dp.children.length > 0 && dp.children[0].product.productTypeCode == productType)).children[0].product.name
 : (this.deal.packages.find(p  => p.isSelected).dealProducts.find(dp => (dp.children.length === 0 && dp.product.productTypeCode === productType)))
 ? this.deal.packages.find(p  => p.isSelected).dealProducts.find(dp => (dp.children.length === 0 && dp.product.productTypeCode === productType)).product.name
 : 'Product not found';
}

By the way, it is advisable to consider extracting methods for do_a and do_b for better code organization.

What is the best way to swap out the if else statement with a Ternary operator within a JavaScript function?

Answer №1

Answer №2

Answer №3

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