What is the best way to update an array in TypeScript when the elements are of different types and the secondary array has a different type as

const usersData = [
    { "id": 0, "name": "ABC" },
    { "id": 1, "name": "XYZ" }
];

let dataList = [];

// How can I transfer the data from the user array to the dataList array?

// If I use the map function, do I need to initialize empty values for other fields in dataList?

If I want to move the user data array to dataList array how can I do that?

If I use map function then do I need to initialize empty data for other fields for dataList?

Answer ā„–1

The map method in JavaScript returns an array, making it easy to transform data:

const dataList = user.map((x: any) => ({
  id: x.id,
  name: x.name,
  address:...
  // add more properties here
}));

When working in "strict mode", you can specify only certain properties to include and use type casting:

const dataList = user.map((x: any) => ({
  id: x.id,
  name: x.name,
  address:...
  // include specific properties
} as { id: number, name: string, 
       address: string , pin: string, 
       comment: string});

Utilize interfaces for type checking:

export interface DataModel {
     id: number;
     name: string;
     address: string;
     pin: string;
     comment: string;
}

const dataList: DataModel[] = user.map((x: any) => ({
  id: x.id,
  name: x.name,
} as DataModel));

An alternative approach without using the map method:

const data = [];
for (let i = 0; i < user.length; i++) {
   data.push({
       id: user[i].id,
       name: user[i].name
   });
}
return data;

Answer ā„–2

Absolutely, initializing empty data is essential.

Check out this straightforward example.

let employee: { id: number, name: string }[] = [
    { "id": 0, "name": "John Doe" },
    { "id": 1, "name": "Jane Smith" }
];

let empDataList: { id: number, name: string, department: string, position: string, salary: number }[] = employee.map(emp => {
    return {
        id: emp.id,
        name: emp.name,
        department: "",
        position: "",
        salary: 0
    };
});

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