What is the correct way to destructure a tuple in Typescript when only certain values will be assigned to new variables?

When writing code, I frequently encounter situations that resemble the following:

function example(parameter: string) {
    const tuple = [
        "newParameterValue",
        "newVariableValue"
    ]
    let newVar;
    [parameter, newVar] = tuple;
}

(Typically, this also involves async/await and Promise.all, where multiple async operations are run in parallel. However, these specifics are not pertinent to the current query). The key issue is that I need to destructure a tuple, assigning one value to an existing variable while creating a new variable for another value.

The approach works, but I find it cumbersome as I have to declare newVar using let rather than

const</code, and separate its declaration from assignment. This method feels inefficient and messy. Ideally, I would prefer something like:</p>

<pre><code>function example(parameter: string) {
    const tuple = [
        "newParameterValue",
        "newVariableValue"
    ]
    [parameter, const newVar] = tuple;
}

Unfortunately, this syntax does not compile.

What is the correct and standard way to write this code?

Answer №1

It is important to consider how you will use it before deciding whether it should be const or let. What version of TypeScript are you currently using?

In the latest version, there seems to be issues with transpilation and assigning to function parameters may not look good.

  function example(parameter: string) {
    const tuple: [string, string] = [
        "newParameterValue",
        "newVariableValue"
    ];
    const [newParameter, newVar] = tuple;
  }

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