What is the correct way to specify the type in my functional component?

I was trying to define the type in my component in a different way, I know it can be done using classes but is there a way to achieve this with functional components without exporting the interface? Despite my extensive research, I couldn't find any relevant information on this.

const Elem1 = forwardRef((props : any, ref : { open()? : void }) => {
   useImperativeHandle(ref, () => ({
       open: () => console.log('opened')
   }))

   ....

})

const Elem2 = () => {
    const elem1Ref = useRef<Elem1>()

    elem1Ref?.current?.open()

    ....

}

Answer №1

To correctly implement this, it is essential to utilize the type parameters specified in the TS Generics definition of forwardRef. Here is an example:

const Component = forwardRef<RefType, PropsType>((props, ref) => {
  ...
}

Answer №2

After conducting extensive research, it appears that the ability to declare the type of a functional component by exporting the component's separate interface is not feasible. Thank you for your help nonetheless!

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