What is the maximum number of groupings that can be created from a set of numbers within a

Question

What is the maximum number of groupings that can be created from a set of numbers within a

I'm trying to figure out how to handle a specific task, but I'm running into some obstacles.

When adding numbers to clusters, a number is considered to belong to a cluster if its distance to at least one existing number in the cluster is within a preconfigured spacing limit. If a new number does not fit any existing clusters, it forms a new cluster. In cases where a new number falls between two nearby clusters, it can be part of both, leading to their merge.

For example:
[100, 0, 7, -89, 80, 86, -100, 2, 81]
This input should result in 5 clusters.

I've managed to create a solution, but it only works when inputting numbers in ascending order:

accept = (value: number): void => {
    if (this.previous == undefined || Math.abs((this.previous) - value) > this.spacing) {
        this.counter++;
    }
    this.previous = value;
}

I have to enter data one by one because the tests are set up like this:

it("custom spacing test", () => {
    detector.accept(4);
    detector.accept(7);
    expect(detector.clusterCount()).toEqual(2);
});

javascript typescript

Answer 1

Answer №1

Sure thing, I'll make sure to include all the details here.

In order to update the accept method, I am considering creating an array to sort each time and then checking if the value falls within the range of the previous and next numbers after placing it in the array. However, I have not yet written the implementation for this.

export class MyLinearClusterDetectorFactory implements LinearClusterDetectorFactory {
  create(spacing: number): LinearClusterDetector {
    return new MyLinearClusterDetector(spacing);
  }
}

class MyLinearClusterDetector implements LinearClusterDetector {
  constructor(readonly spacing: number) {}
  
  counter = 0;
  previous: number | undefined;
  
  accept = (value: number): void => {
    if (this.previous == undefined || Math.abs((this.previous) - value) > this.spacing) {
      this.counter++;
    }
    this.previous = value;
  }

  clusterCount = (): number => {
    return this.counter;
  }
}

}

I already have tests in place:

describe("Basic testing with spacing 2", () => {
  let detector: LinearClusterDetector;
  
  beforeEach(() => {
    detector = new MyLinearClusterDetectorFactory().create(2);
  });

  it("returns 0 if never called", () => {
    expect(detector.clusterCount()).toEqual(0);
  });

  it("returns 1 if called once", () => {
    detector.accept(1);
    expect(detector.clusterCount()).toEqual(1);
  });

  it("returns 1 if called with overlapping", () => {
    detector.accept(1);
    detector.accept(2);
    expect(detector.clusterCount()).toEqual(1);
  });

  it("returns 2 if called with evidently non-overlapping", () => {
    detector.accept(1);
    detector.accept(4);
    expect(detector.clusterCount()).toEqual(2);
  });
  
  it("mine spacing 2", () => {
    detector.accept(4);
    detector.accept(7);
    expect(detector.clusterCount()).toEqual(2);
  });
});

}

Answer 2

Sure thing, I'll make sure to include all the details here.

In order to update the accept method, I am considering creating an array to sort each time and then checking if the value falls within the range of the previous and next numbers after placing it in the array. However, I have not yet written the implementation for this.

export class MyLinearClusterDetectorFactory implements LinearClusterDetectorFactory {
  create(spacing: number): LinearClusterDetector {
    return new MyLinearClusterDetector(spacing);
  }
}

class MyLinearClusterDetector implements LinearClusterDetector {
  constructor(readonly spacing: number) {}
  
  counter = 0;
  previous: number | undefined;
  
  accept = (value: number): void => {
    if (this.previous == undefined || Math.abs((this.previous) - value) > this.spacing) {
      this.counter++;
    }
    this.previous = value;
  }

  clusterCount = (): number => {
    return this.counter;
  }
}

}

I already have tests in place:

describe("Basic testing with spacing 2", () => {
  let detector: LinearClusterDetector;
  
  beforeEach(() => {
    detector = new MyLinearClusterDetectorFactory().create(2);
  });

  it("returns 0 if never called", () => {
    expect(detector.clusterCount()).toEqual(0);
  });

  it("returns 1 if called once", () => {
    detector.accept(1);
    expect(detector.clusterCount()).toEqual(1);
  });

  it("returns 1 if called with overlapping", () => {
    detector.accept(1);
    detector.accept(2);
    expect(detector.clusterCount()).toEqual(1);
  });

  it("returns 2 if called with evidently non-overlapping", () => {
    detector.accept(1);
    detector.accept(4);
    expect(detector.clusterCount()).toEqual(2);
  });
  
  it("mine spacing 2", () => {
    detector.accept(4);
    detector.accept(7);
    expect(detector.clusterCount()).toEqual(2);
  });
});

}

Answer 3

Answer №2

To find the longest cluster in arrays, you can combine them and return the count of the largest cluster.

const
    getMaxClusterSize = (array, space) => {
        return array
            .reduce((r, v) => {
                const [temp, filtered] = r.reduce((q, a) => {
                    q[+a.some(w => Math.abs(v - w) <= space)].push(a);
                    return q;
                }, [[], []]);

                temp.push(filtered.length
                    ? [...filtered.flat(), v]
                    : [v]
                );
                return temp;
            }, [])
            // .reduce((a, b) => a.length > b.length ? a : b)
            // .length; 
    };
    

console.log(getMaxClusterSize([100, 0, 7, -89, 80, 86, -100, 2, 81], 15)); // 4

Answer 4

To find the longest cluster in arrays, you can combine them and return the count of the largest cluster.

const
    getMaxClusterSize = (array, space) => {
        return array
            .reduce((r, v) => {
                const [temp, filtered] = r.reduce((q, a) => {
                    q[+a.some(w => Math.abs(v - w) <= space)].push(a);
                    return q;
                }, [[], []]);

                temp.push(filtered.length
                    ? [...filtered.flat(), v]
                    : [v]
                );
                return temp;
            }, [])
            // .reduce((a, b) => a.length > b.length ? a : b)
            // .length; 
    };
    

console.log(getMaxClusterSize([100, 0, 7, -89, 80, 86, -100, 2, 81], 15)); // 4

Answer 5

Answer №3

I initially wanted to leave a comment, but unfortunately my stack-points are running low. Check out this informative wikipedia article for an advanced solution: https://en.wikipedia.org/wiki/Disjoint-set_data_structure

Answer 6

I initially wanted to leave a comment, but unfortunately my stack-points are running low. Check out this informative wikipedia article for an advanced solution: https://en.wikipedia.org/wiki/Disjoint-set_data_structure

What is the maximum number of groupings that can be created from a set of numbers within a

Answer №1

Answer №2

Answer №3

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