What is the method for making an interface extension from a type as optional?

Can you help me create an interface that includes all students and part of a school, ensuring that gender is required for Peter and optional for other students?

export type School = {
  address: string;
  state: string;
};
export type Gender = { gender: boolean};
export type Human = {first: string; last: string};

export interface Student extends Gender, Human{};
//Gender should be optional for Student

export interface Peter extends Student, Pick<School, 'address'>, Gender {};
//Gender must be required for Peter

Answer №1

To address the issue mentioned in the feedback, it is important to ensure that Student extends Partial<Gender> rather than Gender. The error that follows serves as a precautionary measure to avoid inheriting potentially unrelated types for the same attribute. To eliminate this error, you can explicitly include the specified property so that the compiler can resolve it:

export interface Student extends Partial<Gender>, Human { };

export interface Peter extends Student, Pick<School, 'address'>, Gender {
  gender: boolean; // valid
};

Another approach to handle this without duplicates is by utilizing intersection types instead of extends. Although similar, if A extends B, C is true, then A extends B & C should also hold true. However, due to syntax restrictions limiting implements or extends clauses in type declarations to named types with known property names:

export interface Student extends Partial<Gender>, Human { };

export interface Peter extends Pick<School, 'address'>, (Student & Gender) { }; // encountered an error!
//  --------------------------------------------------> ~~~~~~~~~~~~~~~~~~
// An interface can only extend an identifier/qualified-name with optional type arguments.

Fortunately, since Student & Gender has statically known properties, providing it with a name resolves the issue:

export type GenderedStudent = Student & Gender;
export interface Peter extends Pick<School, 'address'>, GenderedStudent { }; // no errors

This implementation works smoothly.


In both scenarios presented, Student does not necessitate Gender, whereas Peter requires it (oddly enough representing individuals named "Peter"):

const s: Student = {
  first: "Harry",
  last: "Potter"
}; // valid

const p: Peter = {
  first: "Peter",
  last: "Pettigrew",
  address: "Gryffindor House, Hogwarts",
  gender: true // correct as Peter possesses a gender
}; // valid

const badP: Peter = {
  first: "Peter",
  last: "Pettigrew",
  address: "Ron Weasley's pocket",      
}; // incorrect, missing gender

These insights are intended to assist you in resolving your concern. Good luck!

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