What is the most effective approach for revealing AngularJS controller methods in TypeScript?

I have been exploring a way to attach the controller object to the scope in a different manner. Here is an example of how it can be achieved.

interface IAppCtrlScope extends ng.IScope {
   info: any;
}

class InfoCtrl {
    header: string;
    name: string;

    public static $inject = ["$scope"];
    constructor(private $scope: IAppCtrlScope) {        
       this.$scope.info= this; //expose controller
    }

    getData(): void {
      //perform some actions
    }    
}

When implementing this, the view HTML code would look like the following:

<div ng-controller="InfoCtrl">
    <div class="rm-dialog-header">{{info.header}}</div>
    <span ng-click="info.getData()">{{info.name}}</span>
</div>

However, I am curious if there is a way to simplify the controllers' exposure so that I don't need to use 'info.' prefix for each scope variable. This would result in a cleaner view structure like this:

<div ng-controller="InfoCtrl">
    <div class="rm-dialog-header">{{header}}</div>
    <span ng-click="getData()">{{name}}</span>
</div>

I am wondering if there is a way to achieve this or if I might have overlooked something in my approach.

Answer №1

If you want to make methods from your class accessible on the $scope object, you can do so by following these steps:

interface IAppCtrlScope extends ng.IScope {
   getData: () => void;
}

class InfoCtrl {
    header: string;
    name: string;

    public static $inject = ["$scope"];
    
    constructor(private $scope: IAppCtrlScope) {        
       $scope.getData = this.getData; //expose method
    }

    getData = () => {
      //do something
    }    
}

After that, in your HTML markup, you can bind directly to the getData() method.

Just remember to declare your method using the syntax method = () => {}. This will ensure that the method is placed on the instance rather than the prototype.

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