What is the most effective method for identifying duplicate values in a multidimensional array using typescript or javascript?

Question

What is the most effective method for identifying duplicate values in a multidimensional array using typescript or javascript?

I have a 2D array as shown below:

  array =  [ [ 1, 1 ], [ 1, 2 ], [ 1, 1 ], [ 2, 3 ] ]

I am looking to compare the values in the array indexes to check for duplicates. For example

 array[0] = [1,1];
 array[1] = [1,2];
 array[2] = [1,1];

We can see that the values at index 0 and 2 are the same, which is [1,1]. In this case, I want to return a true flag. What is the most efficient way to achieve this? Are there different methods to accomplish this task? Any suggestions or help with explanations would be greatly appreciated. Thank you in advance.

javascript arrays typescript multidimensional-array

Answer 1

Answer №1

To achieve this, you can convert the inner array elements into strings for comparison purposes.

Example :

const arr = [[ 1, 1 ], [ 1, 2 ], [ 1, 1 ], [ 2, 3 ]];

const stringConversion = arr.map((item) => JSON.stringify(item))

const duplicateElements = stringConversion.filter((item, index) => stringConversion.indexOf(item) !== index)

console.log(duplicateElements.length ? true : false);

Answer 2

To achieve this, you can convert the inner array elements into strings for comparison purposes.

Example :

const arr = [[ 1, 1 ], [ 1, 2 ], [ 1, 1 ], [ 2, 3 ]];

const stringConversion = arr.map((item) => JSON.stringify(item))

const duplicateElements = stringConversion.filter((item, index) => stringConversion.indexOf(item) !== index)

console.log(duplicateElements.length ? true : false);

Answer 3

Answer №2

Here is a suggestion on how to tackle this:

Iterate through each element in the multidimensional array.
Compare the two elements by accessing the "row" using index 0 and index 1.

You have the option to utilize various methods for looping through the array. Below is an example of one approach I experimented with:

// ARRAY DECLARATION
let array = [[1, 1], [1, 2], [1, 1], [2, 3]];

// ITERATING THROUGH THE ARRAY 
for (let row of array)
{
  // OUTPUT THE BOOLEAN VALUE TO CONSOLE OR SIMILAR DESTINATION
  console.log(row[0] == row[1]);
}

Answer 4

Here is a suggestion on how to tackle this:

Iterate through each element in the multidimensional array.
Compare the two elements by accessing the "row" using index 0 and index 1.

You have the option to utilize various methods for looping through the array. Below is an example of one approach I experimented with:

// ARRAY DECLARATION
let array = [[1, 1], [1, 2], [1, 1], [2, 3]];

// ITERATING THROUGH THE ARRAY 
for (let row of array)
{
  // OUTPUT THE BOOLEAN VALUE TO CONSOLE OR SIMILAR DESTINATION
  console.log(row[0] == row[1]);
}

Answer 5

Answer №3

Utilize the String method to transform an array into a one-dimensional array of strings and utilize some to verify if there are any duplicated elements:

const arr = [[1, 1], [1, 2], [1, 1], [2, 3]];

const result = arr.map(String).some((v, i, a) => a.indexOf(v) !== i);

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 6

Utilize the String method to transform an array into a one-dimensional array of strings and utilize some to verify if there are any duplicated elements:

const arr = [[1, 1], [1, 2], [1, 1], [2, 3]];

const result = arr.map(String).some((v, i, a) => a.indexOf(v) !== i);

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

What is the most effective method for identifying duplicate values in a multidimensional array using typescript or javascript?

Answer №1

Answer №2

Answer №3

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