I have been searching for various Q&A on ways to efficiently save and sort IPs in a mongo db, but I am struggling to find a solution. Firstly: how should I save an IP address? As a string? Integer? Something else? Secondly: Once saved (let's say from 10.1.0.20 to 10.1.1.255), I need to retrieve the highest IP in my database and then increment it by 1. How can I achieve this? What is the most effective method for retrieval? Is using
this.model.findOne().sort({"staticIp": -1}).exec();
While I don't have a complete solution, what about saving the IP address as an array? It seems like it could work since an IP can easily be stored in an array:
var ip = [192,168,1,1];
This approach would allow you to sort the IPs based on the first element, and then proceed to sort them further if needed.
If anyone proficient in MongoDB could provide assistance with this, it would be greatly appreciated!
(For details on IPv6, please refer to the provided link) An IP address is virtually meaningless without a subnet mask ranging from 1 to 32 in most scenarios. This provides information about which subnet the host belongs to and enables grouping by subnets based on your specific requirements.
You now have the option to store them as a 32-bit unsigned integer
or as a
or a binary string
However, an IP address without a mask is akin to having just a house number without a street address in most systems. Therefore, with the mask, you can perform network calculations to determine all hosts within the same network segment and ascertain the remaining available addresses.
In my opinion, utilizing an unsigned integer along with a separate integer to hold the mask is the preferable approach, followed by employing sorted insertions/deletions.
I recommend checking out this insightful answer on a related topic
Best of luck!
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