Answer №1

To achieve this, the most reliable method is to combine string with an empty set {}. When combining, any already existing string literal types in string will take precedence over those in the intersection (as they are redundant for type validation).

type color = 'white' | 'black' | (string & {}); 

Check it out here as well!

Answer №2

When dealing with union types in TypeScript, it's important to note that the 'string' type may not always behave as expected. Instead of using 'string', consider using 'String' for better results.

type color = 'white' | 'black' | String;

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