What is the process for using infer to determine the return type of a void function?

I am trying to gain a better understanding of how to utilize the infer keyword in TypeScript.

Is this an appropriate example demonstrating the correct usage of infer?

I simply want to infer the return type of the function below:

const [name, setName] = useState<string>('');
const [age, setAge] = useState<number>();

type CallbackType<T> = T extends () => infer R ? R: never

function stateCallback<T>(name: string, age: number): CallbackType<T>{
  setName(name)
  setAge(age);
}

Since I am not returning anything, it should result in a void type. Is this the correct use of the infer keyword?

Playground

Answer №1

Incorrect usage of the infer keyword is not recommended. If you wish for TypeScript to automatically determine the return type of a function, simply omit specifying a return type.

function displayInfo(name: string, age: number) {
  setName(name)
  setAge(age);
}
// The return type of displayInfo will be inferred as void

The infer term serves multiple purposes, including extracting information from a type. When you provide a function type to CallbackType, it will output the returned value's type.

type CallbackType<T> = T extends () => infer R ? R : never

type Output = CallbackType<() => string>
// -> string

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