What is the process of applying arguments to a class constructor automatically?

In my code, there is an ES6 class called User and a global function named map():

class User {
  constructor(public name: string) {}
}

const map = <T, R>(project: (value: T) => R) => {}

Instead of the usual way of calling map like this:

map((value) => new User(value))

I am curious if it's possible to do something like this:

map(new User)

I am unsure whether this approach is feasible. Any thoughts?

Answer №1

To enhance your class, you can implement a static function that receives the value parameter and generates a fresh User instance:

class User {
  static generateUser(value) {
    return new User(value)
  }
}

You can then proceed to utilize it like this:

map(User.generateUser)

Answer №2

If you want to achieve this, it cannot be done directly. One approach is by controlling the target function instead of using the stock map function. In this case, you can modify the function to take a constructor as an argument:

class User { constructor(private id: number) { }}
function map<TIn, T>(value: TIn, ctor: new (a: TIn) => T): T{
    return new ctor(value)
}
map(10, User)

Alternatively, you can utilize a helper function that transforms the constructor into the desired function. While this method may not offer significant brevity compared to the original solution, it provides more flexibility:

class User { constructor(private id: number) { }}
function ctor<TIn, T>(ctor: new (a: TIn) => T): (value: TIn) => T{
    return value => new ctor(value)
}
[10, 11].map(ctor(User));

Answer №3

To ensure that a function is called with the 'new' keyword, you can use the new.target check. If the function is not called with 'new', you can then call the function with new.

function Person(name) {
    if (!new.target) return new Person(...arguments);
    this.name = name;
}

var names = ['Jane', 'Dan', 'Grace', 'Paul'],
    instances = names.map(Person);

console.log(instances);

Answer №4

The concept you are referring to is known as a scope-safe constructor. This approach involves modifying a constructor so that it can function both with and without the use of the new keyword.

interface User {
  name: string;
}

interface UserConstructor {
  new (name: string): User;
  (name: string): User;
}

A similar technique is employed for built-in objects such as Array and Date.

The key is to determine whether the new keyword was utilized:

const User = function (this: User | void, name: string): User {
  if (!(this instanceof User)) {
    return new User(name);
  }

  this.name = name;
  return this;
} as UserConstructor;

This modification makes your class independent of the use of new.

console.log(
  new User('Bob'),
  User('Alice'),
);

As a result, we can now write:

['Alice', 'Bob'].map(User); // $ExpectType User[]

Answer №5

The ongoing debate between object-oriented programming and functional programming in JavaScript often brings up the issue of class constructors versus function constructors.

With ES6 classes requiring the use of the new operator, it becomes tricky to do something like map(new User).

To work around this limitation, a common approach is to create a wrapper around the class constructor that allows instances to be created through a function call. One effective method, as suggested by @baboo, is shown below:

class MyClass {
  // ...

  static create(...args) {
    return new MyClass(...args)
  }
}
const a = new MyClass('hello', [])
const b = MyClass.create('world', 123])

To delve deeper into the challenges posed by the new operator, you can refer to this article.

For those interested in exploring alternative solutions, consider looking into daggy - Library for creating tagged constructors.

Answer №6

In case you are in need of a universal remedy and unable to alter the specified classes, one option is to employ a higher-order function:

function create(class) {
    return (...parameters) => new class(...parameters);
}

// Instead of:
map((value) => new User(value));

// You can use:
map(create(User));

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