What is the proper way to specify the file type when I aim to broaden the current type?

I am working with an existing native type called File, and I have a requirement to extend it by adding a field called id. This is how my code currently looks:

type FileWithId = File & {
  id: number;
};

const ATTACHMENTS = [
  {
    name: "some_file_name.txt",
    ...
  },
  {
    name: "some_file_name2.txt",
    ...
  }
];

const files = ATTACHMENTS.map((attachment) => {
  const file: FileWithId = new File([], attachment.name);
  file.id = attachment.id;
  return file;
});

However, TypeScript is displaying an error message:

TS2322: Type 'File' is not assignable to type 'Attachment'.
    Property 'id' is missing in type 'File' but required in type '{ id: number; }'.

If I remove the casting of type FileWithId for file, then the error becomes:

TS2339: Property 'id' does not exist on type 'File'.

Making the field id optional resolves the issue at this point, but it leads to errors in other parts of my code. I want to highlight that id is a required property in my type.

Casting the type like this:

const file = new File([], attachment.name) as FileWithId;

is not ideal for various reasons.

Is there a better way to solve this problem?

Answer №1

To include the id in the File and then send it back without a variable, you can do this:

const documents = ATTACHMENTS.map((attachment) => Object.assign(new File([], attachment.name), { id: attachment.id }));

An alternative method is to use spreading like so:

const docs = ATTACHMENTS.map((attachment) => ({ ...new File([], attachment.name), id: attachment.id }));

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