What is the reason behind the return type of 'MyType | undefined' for Array<MyType>.find(...) method?

Currently, I am in the process of developing an Angular application using TypeScript. As part of this project, I have defined several classes along with corresponding interfaces that align perfectly with their respective properties:

Map:

export class Map extends BaseObject implements IMap {
    Dimensions: Dimension[];
    Shapes: Shape[];
    Roles: Role[];
}

BaseObject:

export class BaseObject implements IBaseObject {
    ID: string;
    Label: string;
    DataType: string;
    CreatedDate: Date;
    CreatedUser: string;
    UpdatedDate: Date;
    UpdatedUser: string;
}

Within my codebase, there is a service method where the mapArray() function generates an array of Map objects (explicitly declared as Map[]):

Service Method Example:

getMap(id: string): Observable<Map> {
    return of(mapArray().find(map => map.ID === id));
}

The structure of this method closely resembles an example in an Angular tutorial:

Angular Tutorial - Service Method:

getHero(id: number): Observable<Hero> {
  this.messageService.add(`HeroService: fetched hero id=${id}`);
  return of(HEROES.find(hero => hero.id === id));
}

However, I am encountering an error on the return line of my service method:

Type 'Observable<Map | undefined>' is not assignable to type 'Observable<Map>'.

Upon comparison with the tutorial code, it appears that while the .find() method in my implementation returns a type Map | undefined, the tutorial's method returns a type Hero.

What could be causing this discrepancy in behavior?

Answer №1

Why is there a discrepancy in behavior?

The culprit lies within the strictNullChecks option.

Reasoning

This issue arises because Array.prototype.find does indeed return undefined.

Solution

If you are certain that the item will be found, you can assert it like so:

getMap(id: string): Observable<Map> {
    return of(mapArray().find(map => map.ID === id)!);
}

Further Reading

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