What is the reasoning behind TypeScript's assumption that array element lookup will not result in undefined?

It is quite surprising that this snippet of typescript does not throw a type error, which you can also test in the typescript sandbox:

class Foo {
  constructor(readonly x: number, readonly y: number) {}
}

const xOfFirstFoo = (arr: Array<Foo>): number => {
  return arr[0].x
}

const result = xOfFirstFoo([]);
// The above line results in:
// [ERR]: "Executed JavaScript Failed:" 
// [ERR]: Cannot read property 'x' of undefined 

One would assume that the typer should recognize that arr[0] (or any arr[i]) could either be a Foo or undefined, and therefore it cannot guarantee the presence of an .x property.

So, what's really happening here?

Answer №1

I want to give a big shoutout to @jonrsharpe and @shinigami for their invaluable insights that really helped me grasp this concept! To sum it up:

  1. Think of arrays as essentially { [index: number]: T }, where each value at a certain index is expected to have a corresponding defined T value. If you're looking for a specific length, consider using a tuple type.

  2. However, with the introduction of the flag --noUncheckedIndexedAccess in TypeScript 4.1, the behavior will align more closely with what I initially expected. This means:

In this updated mode, every property access (e.g., foo.bar) or indexed access (e.g., foo["bar"]) is now considered potentially undefined.

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