What is the reasoning behind TypeScript's decision to permit the omission of a function's return type?

After setting noImplicitAny to true in my tsconfig, I was surprised to find that I could still omit function return types. One instance is a getter function as shown below:

get name() {
    return `${this.valueName} of ${this.suitName}`;
}

Inquiry 1: Can you identify the return type of the name() getter - is it any?

Inquiry 2: Assuming the return type is any, what is the reason behind this being permissible even with noImplicitAny set to true?

Answer №1

ImplicitAny configuration in TypeScript requires you to specify a type when inference is not possible. For example:

let x;
function f(a) {
   x = a;
} 

In this scenario, TypeScript cannot determine the type of a or x automatically, prompting the compiler to warn about implicit usage of any.

However, in cases like:

// Verbose
const x : string = "hi";
// Compact yet enough
const x = "hi";

You are not obligated to explicitly define every argument or variable, as shown above with string type inference for the constant x.

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