What measures can I take to address the TypeScript error indicating that my function is missing a return statement and the return type does not include 'undefined' in my code?

In this scenario, there is a straightforward function called make which utilizes the handle function to retry a specified number of times if it encounters an error. Once all retries have been exhausted, the make function should throw the error.

const handle = async (): Promise<string> => 'hi';

const make = async (): Promise<string> => {
  const MAX_RETRIES = 2;
  for (let idx = 0; idx <= MAX_RETRIES; idx++) {
    try {
      return await handle();
    } catch (err) {
      if (idx < MAX_RETRIES) {
        continue;
      } else {
        throw err;
      }
    }
  }
};

When utilizing TypeScript, an issue arises as the return type does not include undefined:

Function lacks ending return statement and return type does not include 'undefined'.

You can view this code in the TS Playground.

The main question is how to manage the return type for this function.

It's important to note that:

  • No alterations are to be made to existing tsconfigs (currently set to strict)
  • Avoid changing the return type to
    Promise<string | undefined>

As per understanding, the make function will either return a string during the try block or ultimately throw an error after exhausting retries. Thus, where does the request for undefined from TypeScript originate? Is anything being overlooked?

Answer №1

From my perspective, the make function is limited to either returning a string (within the try block) or throwing an error after exhausting all retries.

I believe you're correct, however, TypeScript struggles to comprehend such intricate logic. Consequently, it incorrectly identifies a path through the function that lacks an explicit return, implicitly resulting in the return of undefined (enclosed in a promise).

To resolve this issue, there are a few possible solutions:

  1. Append a return ""; at the end with a comment indicating its impossibility. (Not ideal.)
  2. Add a
    throw new Error("Logic error, this will never be reached.");
    at the conclusion.
  3. Rework the function to clearly present the final attempt as either a return or throw scenario by using < instead of <= and reiterating the return await handle(); at the end. (Although repetitive, it simplifies the process.)

In my opinion, #2 stands out as the best solution (or possibly jcalz's revisal), yet any of these methods will appease TypeScript—it ultimately boils down to personal preference.

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