What methods does TypeScript use to verify primitive types during runtime?

Is it true that Typescript removes any type or interface at compile time? If so, how is it possible to determine an object's primitive type using the typeof keyword? Are custom interfaces handled differently than primitive types?

const a = "string";
const b = 123;
const c = {};
const d = undefined

console.log(typeof a) -> 'string'
console.log(typeof b) -> 'number'
console.log(typeof c) -> 'Object'
console.log(typeof d) -> 'undefined'

Answer №1

typeof is a key operator in JavaScript.

In Typescript, the language leverages JS operators like typeof to facilitate tasks such as narrowing types during compilation.

For example:

declare const foo: string | number | Function | boolean

function bar() {
    switch (typeof (foo)) {
        case "string":
            return foo.toLowerCase()
        case "number":
            return foo.toExponential()
        case "boolean":
            return foo
        default:
            return foo()
    }
}

Try it out on the Playground

Answer №2

TS does not perform runtime validations.

The confusion may arise from the fact that typeof is a built-in operator in JS.

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