What prevents the right side of this conditional type from being defined as never?

During type-checking time, I have a rule to enforce regarding the parameters that can be passed to my function.

The type is described in the following code snippet:

type CheckConf<TConf extends SupportedConf> = {
  [Key in keyof TConf]: TConf[Key] extends SupportedConf[string]
    ? [Key, [Key, Key]]
    : TConf[Key]; ⬅⬅⬅
};

This type is used as shown below:

declare function check<TConf extends SupportedConf>(

  params: CheckConf<TConf>
): TConf[keyof TConf];

check({ a: ["a", ["a", "a"]], b: ["b", ["b", "b"]] });

check(
  
  { a: ["a", ["a", "b"]] }
);


check({ a: ["a", true] });

For more details and interactive testing, visit this live playground link.

I successfully implemented the CheckConf type but encountered difficulty with understanding the behavior of using never in certain contexts. What theory explains this behavior, and why is never not suitable in these cases?

Answer №1

It is my belief that if a particular type fails to pass the extends check, it is fundamentally incorrect.

type Check<T extends readonly [string, string]> = T extends readonly [string, string]
  ? readonly [T[0], `${T[0]}-augmented`]
  : never;

In the example above, your rationale may seem valid, but it may result in the type appearing unattractive and unusual based on your scenario.

type Check<T> = T extends readonly [string, string]
  ? readonly [T[0], `${T[0]}-augmented`]
  : T;

T has the potential to be any type (such as string[] where the error was encountered), and your type is contingent upon it. Therefore, it is logical to verify if it extends readonly [string, string] in order to define the type as

readonly [T[0], ${T[0]}-augmented]
, otherwise it remains as T, retaining its original generic type.

This is the functionality of your code; I trust this explanation aids in understanding.

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