What's the best way to convert a Union type into a Tuple with the same number of elements

My goal is to transform the following code snippet:

type UnionType = Variant1 | Variant2

into the desired format below:

type ResultingType = [UnionType, UnionType]

In case the union comprises 3 member types, the tuple should contain 3 elements accordingly.

Answer №1

Are you referring to the concept of "permutation"?

type UnionType = 'a' | 'b'

type UnionPermutation<U, K = U> =
  [U] extends [never]
  ? []
  : U extends any
  ? [U, ...UnionPermutation<Exclude<K, U>>]
  : never

// Example: ['a', 'b'] | ['b', 'a']
type test = UnionPermutation<UnionType>

Link to TypeScript Playground

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