When I try to reverse the words in a string, I am not receiving the desired order

Question

When I try to reverse the words in a string, I am not receiving the desired order

Currently delving into TypeScript, I have set myself the task of crafting a function that takes in a string parameter and reverses each word within the string.

Here is what I aim to achieve with my output:

"This is an example!" ==> "sihT si na !elpmaxe"

The solution I've concocted involves steering clear of built-in methods.

export function reverseWords(str: string): string {
  var newStr = "";
  str.split("");
  for(var i = str.length -1; i >= 0; i--){
    newStr += str[i];
  }
  return newStr;
}

reverseWords("Hi. How are you?")

However, this code yields the following result:

 "This is an example!" ==> !elpmaxe na si sihT

What I am actually striving for is:

 "This is an example!" ==> "sihT si na !elpmaxe"

If anyone could shed some light on where I may be going awry, it would be greatly appreciated.

javascript string typescript loops for-loop

Answer 1

Answer №1

While your function is effective, it currently reverses the entire string instead of just the words within it. To address this, consider incorporating an additional function that utilizes your existing function to specifically reverse individual words:

export function reverseStringWords(str: string): string {
    var words = str.split(" ");
    var revWords = words.map(function(word){
        return reverseWords(word);    
    });
    return revWords.join(" ");
}

To enhance clarity and coherence within the code, you might want to rename your function as reverseWord. This adjustment will offer a more intuitive label in the given context.

Answer 2

While your function is effective, it currently reverses the entire string instead of just the words within it. To address this, consider incorporating an additional function that utilizes your existing function to specifically reverse individual words:

export function reverseStringWords(str: string): string {
    var words = str.split(" ");
    var revWords = words.map(function(word){
        return reverseWords(word);    
    });
    return revWords.join(" ");
}

To enhance clarity and coherence within the code, you might want to rename your function as reverseWord. This adjustment will offer a more intuitive label in the given context.

Answer 3

Answer №2

If you don't wish to reverse the entire string, but instead reverse each word within the string while maintaining their relative positions, you can achieve this by first splitting the string by spaces and then reversing each substring:

const reverse = str => str
  .split(' ')
  .map(word => [...word].reverse().join(''))
  .join(' ');
console.log(reverse("This is an example!"));

Alternatively, if you prefer a manual approach, assuming that the use of split is acceptable:

const reverse = str => {
  const words = str.split(' ');
  const outWords = [];
  for (const word of words) {
    let letter = '';
    for (let i = word.length - 1; i >= 0; i--) {
      letter += word[i];
    }
    outWords.push(letter);
  }
  return outWords.join(' ');
};
console.log(reverse("This is an example!"));

Answer 4

If you don't wish to reverse the entire string, but instead reverse each word within the string while maintaining their relative positions, you can achieve this by first splitting the string by spaces and then reversing each substring:

const reverse = str => str
  .split(' ')
  .map(word => [...word].reverse().join(''))
  .join(' ');
console.log(reverse("This is an example!"));

Alternatively, if you prefer a manual approach, assuming that the use of split is acceptable:

const reverse = str => {
  const words = str.split(' ');
  const outWords = [];
  for (const word of words) {
    let letter = '';
    for (let i = word.length - 1; i >= 0; i--) {
      letter += word[i];
    }
    outWords.push(letter);
  }
  return outWords.join(' ');
};
console.log(reverse("This is an example!"));

When I try to reverse the words in a string, I am not receiving the desired order

Answer №1

Answer №2

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