When the typeof x is determined to be "string", it does not result in narrowing down to just a string, but rather to T & string

Could someone help me understand why type narrowing does not occur in this specific case, and return typing does not work without using:

as NameOrId<T>;

Is there a more efficient way to rewrite the given example?

Here is the example for reference:

interface IdLabel {
  id: number;
}

interface NameLabel {
  name: string;
}

type NameOrId<T extends number | string> = T extends string ? NameLabel : IdLabel;

const createLabel2 = <T extends number | string>(nameOrId: T): NameOrId<T> => {
  if (typeof nameOrId === "string") {
    const result = {
      // why in this case type nameOrId
      // is (parameter) nameOrId: T & string
      // instead of simple string ??
      name: nameOrId,
    } 
    return result;
  }
  return {
    id: 123,
  } as NameOrId<T>;
};

Answer №1

Let's delve into the realm of mathematical sets theory. As per Wikipedia:

In the field of mathematics, when set A contains all elements present in set B, we say that set A is a subset of set B. In this scenario, set B becomes a superset of A. It's worth noting that if sets A and B are not identical, then A is considered a proper subset of B. The relationship where one set is within another is referred to as inclusion (or sometimes containment). Furthermore, even the empty set can be classified as a subset of any given set.

This same principle is applied in typescript when dealing with unions, intersections, and assignments.

For instance, the any type acts as a superset encompassing every conceivable type. Therefore, every primitive, complex, or custom type that exists is essentially a subset of the any type.

Consider number literals — if we define number as [-Infinity, +Infinity], enveloping all numbers, and create type A = 1; since every element in A falls under the number category, A is categorized as a subset of number. This allows for operations like:

let num: number = 1

The same concept applies to string literals. While string encompasses all possible strings, a literal such as type B = 'str' signifies only one feasible value.

To summarize, when assigning values to a variable typed with A, it must align with the subset type of A.

When handling non-primitive types like objects, the superset denotes a less defined type:

type Superset = {a: string}
type Subset = {a: string; b: string}

In typescript, the representation of an empty set is denoted by never. Since the empty set serves as a subset of any type, scenarios like the following are perfectly valid:

const a: number = {} as never;

In the context of generics, A extends B implies that A is a subset of B, rather than being equivalent to B. Consequently, the compiler faces challenges in pinpointing the precise generic argument type, resorting to intersection when type guard assessment is initiated.

For further insights on set theory in typescript, refer to this enlightening blog post

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