Why do callbacks in Typescript fail to compile when their arguments don't match?

In my current project, I encountered a scenario where a React callback led to a contrived example.

interface A {
    a: string
    b: string
}

interface B {
    a: string
    b: string
    c: string
}

function foo(fn: (a: A) => void, a: A) {
    fn(a)
}

function bar(arg: B): void {
    console.log(arg.c)
}

foo(bar, {a: 'a', b: 'b'}) // Surprisingly, this works

This situation reveals that bar can be passed as an argument to foo, even though the number of fields in its first argument exceeds what is expected according to the type declaration. This means that users providing bar as a callback may mistakenly assume they have access to a c string in their argument when they do not actually have it.

It is worth noting that there is some level of type checking on the arguments, as shown by the following failure case:

function baz(arg: string) { }

foo(baz, {a: 'a', b: 'b'}) // This fails as expected

The question arises about the underlying mechanism at play here and whether there is a way to define types more precisely to achieve a behavior closer to the desired outcome.

Answer №1

This scenario appears to be a perfect fit for the utilization of generics. It is essential to ensure that the type passed in as the argument aligns with the function parameter. When these two are assigned the same generic parameter, the compiler will verify their consistency.

interface A {
    a: string
    b: string
}

interface B {
    a: string
    b: string
    c: string
}

function foo<T extends A>(fn: (a: T) => void, a: T & {}) {
    fn(a)
}

function bar(arg: B): void {
    console.log(arg.c)
}

foo(bar, {a: 'a', b: 'b'}) //error

Note that the a parameter within foo is defined as T&{} instead of solely T. This adjustment aims to reduce the priority at that inference site. Since the type T can be inferred from either fn or a, we want to ensure that the compiler gives preference to fn, even if it has the option to choose a type for

T</code that would make both parameters compatible (such as the type <code>A
in this case). While I cannot recall where I read about this behavior being documented, I am confident that a member of the compiler team mentioned its reliability for the foreseeable future :-)

Answer №2

This caught my attention, providing insight into the workings of it. However, it fell short in offering guidance on how to prevent a comparable scenario... :(

Visit this link for further information

Answer №3

An interface acts as a binding agreement that mandates a structure to have specific attributes or behaviors. This principle holds true across various programming languages that incorporate the concept of interfaces.

Consider this illustration:

class X implements Y, Z {
  x: string
  y: string
  z: string    
}

The class X adheres to both Y and Z. Hence, you should be able to utilize instances of X in situations where either Y or Z is required. It would be illogical if that wasn't the case.

Similarly, if you apply for a role that necessitates a computer science degree, possessing additional qualifications shouldn't disqualify you. It would be perplexing if your application was rejected solely due to having extra skills.

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