A function of a specific type that includes mandatory parameters does require input values when the function is

As someone who is learning TypeScript, I have been exploring various sources and courses in order to enhance my skills. However, I have encountered a challenge regarding how to make the compiler prompt for arguments when defining a typed function.

Let's consider a straightforward example: imagine I have a function that expects two strings, firstName and lastName, and should return their concatenation:

type FuncType = (firstName: string, lastName: string) => string;
const getFullName: FuncType = () => "";

It is evident that the function definition here is incomplete. Nevertheless, at this stage of defining the function, I would have expected the compiler to notify me of the missing parameters (firstName and lastName) as they are clearly required based on the type FuncType.

However, that is not happening. Can anyone guide me on what I might be overlooking?

Answer №1

It may sound strange, but this is actually a unique feature of TypeScript. For more information on how functions are compared in TS, you can check out this resource.

In essence, TypeScript allows for the assignment of functions with fewer parameters than the assigned type, utilizing what they call "discarding parameters."

This flexibility is important due to the way JavaScript is used, especially in relation to various APIs that accept callbacks with differing parameter counts. Enforcing strict parameter matching could potentially break a lot of existing code.

The underlying reason for this behavior is rooted in JavaScript's acceptance of optional parameters by default. Therefore, a function with fewer parameters will always be assignable to one with more.

Keep in mind that TypeScript's behavior becomes evident when you actually invoke the function, as illustrated here

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