Adding an item into a list with TypeScript is as simple as inserting it in the correct

I am working with a list and want to insert something between items. I found a way to do it using the reduce method in JavaScript:

const arr = [1, 2, 3];
arr.reduce((all, cur) => [
  ...(all instanceof Array ? all : [all]),
  0,
  cur
])

During the first iteration, the all variable contains the first item and is of type number, but in subsequent iterations it becomes a list. This can be observed by logging output:

arr.reduce((all, cur) => {
  console.log(all);
  return [
    ...(all instanceof Array ? all : [all]),
    0,
    cur
  ]
});
// 1
// [1, 0, 2]
// [1, 0, 2, 0, 3]

This method works perfectly in pure JavaScript, however, there seems to be an issue when applying TypeScript for typing purposes:

arr.reduce((all: number | number[], cur: number) => [
    ...(all instanceof Array ? all : [all]),
    0,
    cur
]);

... which results in the following error:

TS2345: Argument of type '(all: number | number[], cur: number) => number[]' is not assignable to parameter of type '(previousValue: number, currentValue: number, currentIndex: number, array: number[]) => number'.   Type 'number[]' is not assignable to type 'number'.

Is there a different approach that could be used to achieve the same result while utilizing TypeScript?

Answer №1

When working in TypeScript, if you use the reduce method on an array without providing an initial value (meaning the initial value is set to the first element of the array), the type of the previousValue (in this case "all") will be the same as the type of the first entry in the array. If you want to change this behavior, you will need to modify your function to include an initialValue that is an array, like so:

const arr: number[] = [1,2,3]
arr.reduce((all, cur, index) => index === 0
    ? [cur]
    : [...all, 0, cur]
,[])

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