Angular filter by boolean values

Trying to create a filter based on user status, with "Active" for online and "Inactive" for offline. However, filtering by string is presenting challenges as typing "active" still shows offline users due to the presence of "inactive" within it. I am looking to assign a false value to 'inactive' and a true value to 'active' to resolve this issue.

Any advice on how to achieve this? I want the filter options to display "Active" and "Inactive" in the datalist, but when selected, it should pass true or false values to the filter function.

Below is the HTML and TypeScript function I have created:

<input type="text" list="status" placeholder="Status" (keyup)="updateFilter($event)" id="stat">   
    <datalist id="status">
      <option>Active</option>
      <option>Inactive</option>
    </datalist>
updateFilter(event: Event) {
    this.filterValue = (event.target as HTMLInputElement).value;    
    this.dataSource.filter = this.filterValue.trim().toLowerCase();
    console.log(this.dataSource.filter);

    if (this.dataSource.paginator) {
      this.dataSource.paginator.firstPage();
    }
  }

Answer №1

When utilizing Angular Material, you can specify how the filter should be implemented on the data by using the filterPredicate method: https://material.angular.io/components/table/api#MatTableDataSource

To ensure that values are strictly equal instead of just similar, provide an arrow function to your data source like this:

this.datasource.filterPredicate = (data: YourDataType, filter: string) => {
  return data.status === filter;
};

Answer №2

Instead of using datalist, consider using a select element if your filter has strict values. The select element works the same way but prevents users from typing in their own input.

If you are still encountering this issue, simply check if

(event.target as HTMLInputElement).value === 'active'
to resolve it.

I recommend creating an enum in your code to replace magic strings. For example, use UserStatus.active instead of 'active'.

Answer №3

If you want to achieve this, regex is the way to go:

let word1 = 'ativio';
let word2 = 'inativio';

new RegExp('\bativio\b').test(word1); // returns true

new RegExp('\bativio\b').test(word2); // returns false

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