Typescript typically simplifies types if possible:
type A = string | 'literal'; // => string
type B = number | 0; // => number
However, why does it fail to simplify array unions:
type C = (1 | 2)[] | number[]; // => number[] | (1 | 2)[] => Expected: number[]
type D = string[] | 'literal'[]; // => string[] | 'literal'[] => Expected: string[]
Why doesn't TypeScript combine the type into its supertype.
Here's what I discovered:
type MergeSubtypes<T, U = T> = T extends U
? Exclude<U, T> extends infer Rest
? T extends Rest
? never
: T
: never
: never;
It appears to be functioning properly, but perhaps someone could provide further insight into its underlying rationale.
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