Associate the generic operator <T> with a FunctionConstructor

In my TS function, I deserialize JSON into a specific type/object by providing it with a constructor function of that type which reconstructs the object from JSON.

Here is how it looks like:

export function deserializeJSON<T>(JSONString: string, type?: FunctionConstructor, ...

Is there a way to indicate that the argument type: FunctionConstructor represents the constructor of type <T>?

UPDATE

Example usage of deserializeJSON:

const serializedDate = JSON.stringify(new Date);
const deserializedDate = deserializeJSON<Date>(serializedDate, Date);

EDIT

I've discovered that FunctionConstructor means the constructor of Function, so it might be better to label the argument type as type: Function. However, this approach requires casting type to <any> when using new type. Is there a way to express something like <T>.constructor instead?

EDIT

I have created an interface:

interface Constructor<T> extends Function{
    new (): T;
    new (...args: Array<any>): T;
    (...args: Array<any>): T;
    prototype: T;
}

This essentially defines a generic newable Function, but unfortunately, it cannot be assigned to types like DateConstructor. Hence, it's preferable to stick with type: Function since it accepts all constructors.

Answer №1

Responding to my inquiry.

Additional testing is required for this interface, but initial results are promising:

interface Constructor<T> extends Function {
    new (): T;
    new (...args: Array<any>): T;
    prototype: T;
}

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