Avoiding Overload Conflicts: TypeScript and the Power of Generic Methods

I have created an interface type as follows:

interface Input<TOutput> { }
    

And then extended that interface with the following:

interface ExampleInput extends Input<ExampleOutput> { }

    interface ExampleOutput { }
    

Additionally, I have defined a "service" interface like this:

interface Service {
      invoke<TInput extends Input<TOutput>, TOutput>(input: TInput): Observable<TOutput>
    }
    

However, when attempting to call it with an instance of ExampleInput, it fails:

function example(service: Service) {
      service.invoke({} as ExampleInput).subscribe((output: ExampleOutput) => {
        console.log(output);
      });
    }
    
error TS2769: No overload matches this call.
      Overload 1 of 3, '(observer?: Partial<Observer<unknown>> | undefined): Subscription', gave the following error.
        Type '(output: ExampleOutput) => void' has no properties in common with type 'Partial<Observer<unknown>>'.
      Overload 2 of 3, '(next: (value: unknown) => void): Subscription', gave the following error.
        Argument of type '(output: ExampleOutput) => void' is not assignable to parameter of type '(value: unknown) => void'.
          Types of parameters 'output' and 'value' are incompatible.
            Type 'unknown' is not assignable to type 'ExampleOutput'.
      Overload 3 of 3, '(next?: ((value: unknown) => void) | null | undefined, error?: ((error: any) => void) | null | undefined, complete?: (() => void) | null | undefined): Subscription', gave the following error.
        Argument of type '(output: ExampleOutput) => void' is not assignable to parameter of type '(value: unknown) => void'.
          Types of parameters 'output' and 'value' are incompatible.
            Type 'unknown' is not assignable to type 'ExampleOutput'.

    185   service.invoke({} as ExampleInput).subscribe((output: ExampleOutput) => {
                                                     ~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    

Why does the return type of the Observable's subscribe callback show as either unknown or void, when I am expecting it to be ExampleOutput?


To illustrate using a different language example, in JVM Kotlin, the code below compiles and behaves as expected after implementing appropriate functionality:

fun interface Subscriber<TOutput>
    {
        fun subscribe(callback: (output: TOutput) -> Unit): Unit
    }

    interface Input<TOutput>

    interface ExampleInput : Input<ExampleOutput>

    interface ExampleOutput

    interface Service
    {
        fun <TInput : Input<TOutput>, TOutput> invoke(input: TInput): Subscriber<TOutput>
    }

    fun example(service: Service)
    {
        service.invoke(object : ExampleInput { }).subscribe { output: ExampleOutput ->
            println(output)
        }
    }
    

Answer №1

Presently, according to your definition

interface Service {
  invoke<TInput extends Input<TOutput>, TOutput>(input: TInput): Observable<TOutput>
}

this method is defined with an argument that must have the properties of Input<TOutput>, and the return type is unspecified because no value has been provided for it. You can use it like this:

service.invoke<string, number>.subscribe()

You may want to specify generics in your service interface, as there the type is likely known

interface Service<O> {
  invoke(input: Input<O>): Observable<O>
}
function example(service: Service<ExampleOutput>) {
  service.invoke({}).subscribe((output) => {
    console.log(output);
  });
}

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