Can a custom type be created in Typescript that permits objects but excludes Errors?

Currently working on resolving an odd scenario with a logger. Essentially, calls like log({ info: 'information' }) function as expected, but log(new Error()) falls short.
While no solution is readily available, the goal is to override the log method to accept all objects except errors as parameters. Is this achievable in Typescript?

An attempt was made using conditional types:

type NotError<T> = T extends Error ? never : T;

log(NotError<object>): void

Despite this approach, calling log(new Error()) still does not produce any errors or warnings.

Side note: The issue stems from all objects having non-enumerable properties, although our only encountered scenario involving such objects are Errors.

Answer №1

The issue lies in the fact that NotError<object> will simply be resolved to object. To achieve what you desire, it is necessary to make use of generics:

function log<T>(notError: NotError<T>): void {
  console.log(notError);
}

For further information, refer to: https://www.typescriptlang.org/docs/handbook/generics.html

Answer №2

Take a look at this illustrative case

const { createLogger, format } = require('winston');
const LEVEL = Symbol.for('level');

/**
 * Capture only the messages that correspond to the specified `level`.
 */
function filterOnly(level) {
  return format(function (info) {
    if (info[LEVEL] === level) {
      return info;
    }
  })();
}

const logger = createLogger({
  format: zformat,
  transports: [
    // specifically for 'info' level
    new transprts.File({
      level: 'info',
      format: filterOnly('info'),
      filename: 'logs/access.log',
    })name: 'logs/combined.log',
    })
  ]
});

For additional information, refer to filtering object details

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