Can you change the method definition of a built-in class using TypeScript?

Working with the Web Audio Api in TypeScript has presented me with a minor issue. I am trying to enhance AudioParam's prototype by adding some convenience methods that can be used on any parameter. However, I keep getting an error from the compiler stating "Property 'set' does not exist on type 'AudioParam'".


const ctx = new AudioContext()

AudioParam.prototype.set = function (value: number, at?: number, type?: number) {/*implementation*/} // The error occurs here on `set`

Is there a workaround for this?

Appreciate any assistance.

Answer №1

In my experience, achieving this in TypeScript can be broken down into two steps:

  1. Initially, you must implement the JavaScript part (as shown above)
  2. Next, formally declare the new method to the TypeScript compiler for syntax validation

One possible approach is:

AudioParam.prototype.customMethod = function (value: number, at?: number, type?: number) {
/*implementation*/
}
export interface AudioParam {
    customMethod(value: number, at?: number, type?: number);
}

Following this setup, the code snippet below should execute correctly and pass syntax checking:

const myAudioParam = new AudioParam();
myAudioParam.customMethod(1, 2, 3);

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