Can you explain the meaning of the code snippet: ` <TFunction extends Function>(target: TFunction) => TFunction | void`?

As I delve into the contents of the lib.d.ts file, one particular section caught my attention:

declare type ClassDecorator = <TFunction extends Function>(target: TFunction) => TFunction | void;

The syntax in this snippet is a bit perplexing to me. Can someone shed some light on it for me?

From what I gather, a new type called ClassDecorator is being declared here. This type is associated with a function, but what exactly does

<TFunction extends Function>
signify? And why is there an arrow used in the definition?

Answer №1

Describing a type for a generic function using the basic format of

<T>(target: T) => T | void;

Example

type MyFuncType = <T>(target: T) => T | void;

var myFunc: MyFuncType = <T>(target: T) => {
    return target;
}

var stringOrVoidResult = myFunc<string>("test");
var numberOrVoidResult = myFunc<number>(123);

TFunction extends Function indicates that the specified generic function's type, when used, must be of the type Function, which encompasses all classes.

Example

class Animal {
    Eat: () => void;
    Sleep: () => void;
}

type MyFuncType = <T extends Animal>(target: T) => T | void;

var myFunc: MyFuncType = <T>(target: T) => {
    return target;
}

var stringOrVoidResult = myFunc<string>("test"); // Error, as string is not an Animal subtype
var numberOrVoidResult = myFunc<number>(123); // Error, as number is not an Animal subtype

class Dog extends Animal {

}

var dogOrVoidResult = myFunc<Dog>(new Dog()); //Ok, since Dog is an Animal

In the given examples, specifying the generic function's type may not always be necessary as it can be inferred from the input argument by the compiler. However, this is not always the case.

var stringOrVoidResult = myFunc("test");
var numberOrVoidResult = myFunc(123);
var dogOrVoidResult = myFunc(new Dog());

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