"Utilizing Typescript's keyof operator on its own

I'm grappling with the challenge of creating a type that can utilize the typeof its own keys, but I'm hitting a roadblock. Below is a simplified version of what I'm attempting to achieve:

type SpecialType = Record<string, (getter: <K extends keyof SpecialType>(key: K) => ReturnType<SpecialType[K]>) => any>

const yo: SpecialType = {
  a: get => {
    get('b') // okay, should return string type
    return 1 // returns number
  },
  b: get => {
    get('a') // okay, should return number type
    get('c') // should throw an error
    return 'a' // returns string
  }
}

The defined type does not work as expected. My goal is for the parameter get in each function to be limited to the keys of the parent object, and ideally determine the return type of that function based on the key used in get.

My current approach looks something like this;

type SpecialType<T extends Record<string, (getter: <K extends keyof T>(key: K) => ReturnType<T[K]>) => any>> = T

However, this doesn't function without the user explicitly specifying the generic themselves (which I am trying to avoid).

Answer №1

One way to achieve a similar result is by utilizing getters and leveraging the behavior of this in JavaScript. When functions are declared within an object, the keyword this refers to the enclosing object's context, as shown below:

const customObject = {
  get propertyA() {
    this.propertyB; // string
    return 1; // returns a number
  },
  get propertyB(){
    this.propertyA; // number
    return 'A'; // returns a string
  },
};

This approach was commonly used for creating classes before the introduction of the class keyword in ES6. Would this approach meet your requirements?

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