Checking if the return value complies with the Conditional Type specified in the function declaration

I'm currently experimenting with adapting Scott Wlaschin's concept of "Railway Oriented Programming" to Typescript.

I am focusing on ensuring the correct types for the either function. Although I believe my code provided below should be functional, I am encountering compiler errors when it comes to the return statements within the either function.

type Success<T> = {
    success: true,
    result: T
};

type Failure<E> = {
    success: false,
    cause: E
}

export function either<T, E, U, F, I extends Success<T> | Failure<E>>(
    onSuccess: (i: T) => U,
    onFailure: (i: E) => F,
    input: I
  ): I extends Success<T> ? U : I extends Failure<E> ? F : never {
    if (input.success === true) {
      return onSuccess(input.result); // encountering compiler error: Type 'U' is not assignable to type 'I extends Success<T> ? U : I extends Failure<E> ? F : never'
    } else {
      return onFailure(input.cause); // encountering compiler error: Type 'F' is not assignable to type 'I extends Success<T> ? U : I extends Failure<E> ? F : never'
    }
  }

The reason behind this error remains unclear to me. The conditional type indicates that both U and F can be returned, and my code successfully narrows down the type of the input argument. One way to resolve this issue is by utilizing a Type Assertion matching the return type of the function (e.g.

return onSuccess(input.result) as I extends Success<T> ? ....
), but my queries are:

  1. Is employing a Type Assertion the sole solution to eliminate the compiler errors?
  2. If so, why does Typescript struggle to recognize that the return values fulfill the specified return type?

Answer №1

At the moment, TypeScript's control flow analysis does not impact generic type parameters. If you have a variable t of a generic type T, using constructs like switch/case or if/else or ?/: to guard the type of t can narrow its apparent type from T to something else (e.g.,

T & string</code), but it does not affect the type parameter <code>T
itself.

This limitation exists for a reason: you cannot simply re-constrain T. For example, if T extends A | B and after checking isA(t) the type of t is narrowed to A (or T & A), it does not imply that T extends A. It could still be the full union type A | B. This sets a new lower bound for T, not a new upper bound. To express lower bound constraints in TypeScript, there needs to be a way to do so, as discussed in microsoft/TypeScript#14520.

If one desires that T extends A | B means exactly either A or B, excluding unions of those possibilities, a new constraint such as oneof would be needed, as suggested in microsoft/TypeScript#27808. Until this capability is available, utilizing type assertions to signify that isA(t) implies T is A remains the simplest workaround.


While not the only solution to resolve compiler errors, refactoring to avoid control flow analysis when working with generics may be necessary. This involves leveraging operations like indexing with a generic key type on object types or employing mapped types. The details are summarized in microsoft/TypeScript#47109.

Unfortunately, the refactoring process can be cumbersome and intrusive, especially in cases where objects must be indexed with boolean values. Shifting to an enum or other types instead may be required:

enum Bool { FALSE, TRUE }
const _true = Bool.TRUE;
const _false = Bool.FALSE;

The types need to be rewritten to incorporate mapping into explicit types using these keys. An example approach is demonstrated above.

Testing the revised implementation confirms that it compiles without error and no longer relies on type assertions. Thank you.

...

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