I am in possession of an interface that holds keys of various types, and I am interested in creating a new type based on the types of those keys.
interface SomeType {
abc: string;
def: number;
ghi: boolean;
}
The type I want to create:
type SomeOtherType = string | number | boolean
Can this be achieved in TypeScript?
To index with a keyof operator, you can utilize the following code:
interface SomeType {
abc: string;
def: number;
ghi: "sdf";
}
type t = SomeType[keyof SomeType];
The type t will represent a type union derived from the values of the object: https://i.sstatic.net/skSoI.png
A useful technique for generating interface values involves using a clever trick:
interface SomeType {
abc: string;
def: number;
ghi: boolean;
}
//Create a type that functions as a "valueof" (similar to keyof)
type ValueOf<T> = T[keyof T];
//Then extract the values
type Values = ValueOf<SomeType> // Values = string | number | boolean
//ValueOf can be used multiple times, but SomeType[keyof SomeType] is also valid
//If you are looking for the keys instead, simply use "keyof":
type Keys = keyof SomeType // Keys = 'abc' | 'def' | 'ghi'
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