Converting JSON to TypeScript with Angular Casting

Question

Converting JSON to TypeScript with Angular Casting

I'm facing an issue detailed below.

API:

 "Data": [
  {
    "Id": 90110,        
    "Name": "John",
    "Surname": "Doe",       
    "Email": "<a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="472d282f2923282207202a262e2b6924282a">[email protected]</a>",    
    "Status": "Active"
  },
  {
    "Id": 90109,
    "Name": "Sally",
    "Surname": "Doe",        
    "Email": "<a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="f281939e9e8b969d97b2959f939b9edc919d9f">[email protected]</a>",  
    "MiddleName":"II",           
    "Status": "Active"
  }]

Upon parsing the JSON to my typescript class, I noticed that the MiddleName property remains undefined. This is causing issues when exporting to Excel using the 'xlsx' library as shown in the image below. How can I address this problem and set a default value for null or undefined properties?

User Export P.S : I am using 'xlsx' library for excel export.

json angular typescript

Answer 1

Answer №1

In order to assist you with debugging, it would be helpful if you shared the code for your TypeScript class where you parsed the JSON data. Without that information, we are unable to provide specific assistance.

However, if you have created a class that mirrors the structure of the JSON data and want to handle missing properties by assigning them empty strings, you could use the following approach after receiving the API response:

const data = apiJson.map( (person) => {
    Object.assign(
       new Person(), 
       {
         Id: person.Id,
         Name: person.Name || '',
         Surname: person.Surname || '' ,        
         Email: person.Email || '',  
         MiddleName: person.MiddleName || '',           
         Status: person.Status || ''
       }
    )
});

If your class only contains property definitions without any methods, you might consider defining it as an interface instead. In this case, you can simplify the mapping process like so:

const data = apiJson.map( (person) => {
       return {
         Id: person.Id,
         Name: person.Name || '',
         Surname: person.Surname || '' ,        
         Email: person.Email || '',  
         MiddleName: person.MiddleName || '',           
         Status: person.Status || ''
       }
 });

Answer 2

In order to assist you with debugging, it would be helpful if you shared the code for your TypeScript class where you parsed the JSON data. Without that information, we are unable to provide specific assistance.

However, if you have created a class that mirrors the structure of the JSON data and want to handle missing properties by assigning them empty strings, you could use the following approach after receiving the API response:

const data = apiJson.map( (person) => {
    Object.assign(
       new Person(), 
       {
         Id: person.Id,
         Name: person.Name || '',
         Surname: person.Surname || '' ,        
         Email: person.Email || '',  
         MiddleName: person.MiddleName || '',           
         Status: person.Status || ''
       }
    )
});

If your class only contains property definitions without any methods, you might consider defining it as an interface instead. In this case, you can simplify the mapping process like so:

const data = apiJson.map( (person) => {
       return {
         Id: person.Id,
         Name: person.Name || '',
         Surname: person.Surname || '' ,        
         Email: person.Email || '',  
         MiddleName: person.MiddleName || '',           
         Status: person.Status || ''
       }
 });

Converting JSON to TypeScript with Angular Casting

Answer №1

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