for (let i = 0; i < 10; i++) {
setTimeout(function() {
console.log(i);
}, 100 * i);
}
Upon execution, it prints the following output sequentially: 0 1 2 3 4 5 6 7 8 9 However, the concept of multiplying i by 100 in the setTimeout function may seem confusing at first glance.
Utilizing the setTimeout() method allows for the execution of a function or expression after a set interval of time in milliseconds.
During the initial loop, there is a delay of i*100=0, which then progresses to 100, followed by 200 and so forth. As a result, the code logs i on each iteration with varying delays.
i goes through a range from 0 to 9. During each iteration, a timeout is set for i multiplied by 100.
This results in ten timeouts being established for 0ms (0 * 100), 100ms (1 * 100), 200ms (2 * 100), and so forth up to 900ms (9 * 100).
i | i * 100 | delay
--+---------+------
0 | 0 * 100 | 0ms
1 | 1 * 100 | 100ms
2 | 2 * 100 | 200ms
3 | 3 * 100 | 300ms
4 | 4 * 100 | 400ms
5 | 5 * 100 | 500ms
6 | 6 * 100 | 600ms
7 | 7 * 100 | 700ms
8 | 8 * 100 | 800ms
9 | 9 * 100 | 900ms
The For loop is triggering the setTimeout() function a total of 10 times.
To simplify, it can be demonstrated as follows...
setTimeout(function() { console.log(0); }, 0); # when i=0
setTimeout(function() { console.log(1); }, 100); # when i=1
setTimeout(function() { console.log(2); }, 200); # when i=2
setTimeout(function() { console.log(3); }, 300); # when i=3
and so forth...
Essentially, for each number between 0 to 9, the setTimeout function schedules the console.log() method to execute at intervals of 100 ms. Changing this value to 1000 will result in a one second delay between numbers being printed.
If you eliminate the multiplication of i by 100 and keep a constant interval (e.g., only 100), all the numbers will appear to be printed simultaneously after that fixed interval.
Hey there, I really appreciate the help everyone. Being new to this, I was having trouble grasping it at first.
setTimeout(function, parameter)
for (let i = 0; i < 10; i++) {
setTimeout(function() {
console.log(i);
}, 100 * i);
}
During execution, the value of i remains the same after being multiplied by one hundred. Instead, there is a 100ms delay in the output each time, causing an increase of 100ms with every iteration. Ultimately, the total delay amounts to 900ms.
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