Definition of Interface -
interface I {
name: string;
age: number;
size?: string;
}
Arrays Initialization -
let firstArrayMatches: I[] = [];
let firstArrayUnmatches: I[] = [];
let secondArrayMatches: I[] = [];
let secondArrayUnmatches: I[] = [];
Initial Values for First Array -
const firstArray: I[] = [
{
name: 'daniel',
age: 30
},
{
name: 'tamir',
age: 30
}
]
Initial Values for Second Array -
const secondArray: I[] = [
{
name: 'daniel',
age: 30,
size: 'm'
},
{
name: 'ariel',
age: 28,
size: 'm'
}
]
Mapping the Elements in secondArray to return a string[] -
const secondArrayIndexes = secondArray.map(({ name, age }) => name + '/' + age);
Iterate through the firstArray, if there is a match push the object into firstArrayMatches and push ...secondArray.splice(match, 1) into secondArrayMatches. If no match, push the object into firstArrayUnmatches and assign the remaining elements in the second array to secondArrayUnmatches.
for (const o of firstArray) {
const match = secondArrayIndexes.indexOf(o.name + '/' + o.age);
if (match >= 0) {
firstArrayMatches.push(o);
secondArrayMatches.push(...secondArray.splice(match, 1));
} else {
firstArrayUnmatches.push(o);
}
}
secondArrayUnmatches = secondArray;
Output Results -
console.log('First Matching Objects: '+ JSON.stringify(firstArrayMatches))
console.log('First Unmatched Objects: '+ JSON.stringify(firstArrayUnmatches))
console.log('Second Matching Objects: '+ JSON.stringify(secondArrayMatches))
console.log('Second Unmatched Objects: '+ JSON.stringify(secondArrayUnmatches))
Expected Output -
First Matching Objects:
[{"name":"daniel","age":30,"size":"m"}]First Unmatched Objects:
[{"name":"tamir","age":30}] Second Matching Objects:
[{"name":"daniel","age":30,"size":"m"}]Second Unmatched Objects:
[{"name":"ariel","age":28,"size":"m"}]The function should transfer properties from the second array to the first array if there is a match.