Create a Typescript function that adheres to a specified type

Imagine a scenario where a specific type of function is declared within a type

type Callback = (err: Error | null, result: any)
type UselessFunction = (event: string, context: any, callback: Callback) => void

The objective is to declare functions that adhere to the UselessFunction type

The documentation only provides information on how to assign a type to a function using arrow syntax

const someFunction: UselessFunction = (evt, ctx, cb) => {}

Is there a way to assign a type to a function declaration? The syntax is not clear in the documentation

function someFunction (event, context, cb) {
}

Answer №1

When working with TypeScript, you may find that it lacks a specific functionality. To work around this limitation, you must separately add type annotations to the parameters and return value of a function declaration in order to define its specific type. One way to simplify this process is by utilizing the Parameters and ReturnType types.

type CustomFunction = (event: string, context: any, callback: Callback) => void

function someOtherFunction (...params: Parameters<CustomFunction>): ReturnType<CustomFunction> {
  // ...
}

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