Creating a subtype in typescript involves specifying values for certain fields and getting rid of any optional members in the type definition

interface Person{ 
name:string,
age:number,
gender?:string
}
interface Employee extends Person{
name='John Doe',
age:number
}

I am trying to achieve the above structure for a person and employee in TypeScript. I am also curious if something similar can be done using types instead of interfaces. Any insights would be greatly appreciated.

Answer №1

To eliminate optional properties using types instead of interfaces, you can achieve this by defining two types as shown below:

type SampleType = { 
  key1: string,
  key2: boolean,
  key3?: boolean
}

type ResultType = {
    [Key in keyof SampleType as SampleType[Key] extends Required<SampleType>[Key] ? Key : never]: SampleType[Key]
}

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