Creating a type declaration for an object by merging an Array of objects using Typescript

I am facing a challenge with merging objects in an array. Here is an example of what I am working with:

const objectArray = {
  defaults: {
    size: {
      foo: 12,
      bar: {
        default: 12,
        active: 12
      }
    },
    color: {}
  }
}

In addition, I have another object as follows:

const customObject = {
   size: {
     m: '12px'
   }
}

The goal is to merge the contents of objectArray.defaults.size into customObject.size.components. Even though the logic for this merge is straightforward, TypeScript cannot infer the output. To address this, I manually defined the ReturnType using mapped types in TypeScript as shown below:

const mergeObjects = <
  T extends RawTheme,
  D extends ThemeDependency[] = ThemeDependency[],
  A extends number = number
>(
  dependencies: D,
  options?: MergeOptions
): T & {
  size: T['size'] & {
    components?: {
      [Key in KeysOfUnion<
        D[A]['defaults']['size']
      >]: D[A]['defaults']['size'][Key]
    }
  }
}

However, I encountered an issue where I was unable to access the value of a specific object by its index within the array. The value of size.components.bar ended up being unknown. I am seeking suggestions on how to properly resolve this dilemma. Any insights would be greatly appreciated.

For those interested, here is the KeysOfUnion Type reference:

type KeysOfUnion<T> = T extends T ? keyof T : never

Answer №1

During my exploration, I stumbled upon an interesting article at this link: https://dev.to/lucianbc/union-type-merging-in-typescript-9al

This article delves into the concept of merging object unions using custom utility types:

type AllKeys<T> = T extends any ? keyof T : never
type PickType<T, K extends AllKeys<T>> = T extends { [k in K]: any }
  ? T[K]
  : undefined
type PickTypeOf<T, K extends string | number | symbol> = K extends AllKeys<T>
  ? PickType<T, K>
  : never
type Merge<T extends object> = {
  [k in AllKeys<T>]: PickTypeOf<T, k>
}

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