Determine the function's return type based on its arguments

Here is the code snippet:

const handleNodes = (node: Node | Node[]) => {
  if (Array.isArray(node)) {
    return [{}];
  }
  return {};
};

The desired result is:

handleNodes([{}]) // infer that this returns an array
handleNodes({}) // infer that this returns an object

Is there a way to achieve this? I attempted to utilize conditional types, but faced some challenges.

Answer №1

In case the number of arguments remains constant with each function call, you can utilize function overloading as demonstrated below:

type DemoNode = {
    id?: string;
};

// Define different function signatures with respective return types
function handleNodes(node: DemoNode): DemoNode
function handleNodes(node: DemoNode[]): DemoNode[]

// Function implementation
function handleNodes(node: DemoNode | DemoNode[]) {
  if (Array.isArray(node)) {
    return [{}];
  }
  return {};
}

const res1 = handleNodes([]);
    // ^? const res1: DemoNode[]
const res2 = handleNodes({});
    // ^? const res2: DemoNode

Link to TS Playground

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