Discovering the type in Typescript without explicitly defining a type variable for the callback

I am looking for a solution to wrap rxjs subscribe's next callback with my own function:

type Handler<T> = (value: T) => void;

export function withTryCatch<T>(callback?: Handler<T>): Handler<T> {

  return (value: T) => {
    try {
      callback?.(value);
    } catch(err) {
      // error handling
    }
  };
}

The issue with the example below is that it does not automatically infer the type from subscribe's next function. In this case, the user type is identified as unknown. The only way to set the user's desired type is by explicitly defining the type variable T in withTryCatch (see commented code below - withTryCatch<UserModel>).

 store$
    .pipe(
      map(userSelector)
    )
    // .subscribe(withTryCatch<UserModel>((user) => {
    .subscribe(withTryCatch((user) => {
      // possible error code
    }));

Is there a way to avoid using withTryCatch<UserModel>?

Answer №1

This problem arises when using the withTryCatch function, specifically in conjunction with the rxjs subscribe method. When you simply call it without specifying a type parameter T, it remains unknown. However, if you provide a type parameter, then T becomes known. You can leverage Typescript's type inference by explicitly typing the user argument like so:

withTryCatch((user: UserModel) => {

});

To benefit from Typescript inferring, you must pass the callback directly to the subscribe method. Unfortunately, this is not feasible with the current wrapper function.

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