Enclose a data point within a function, excluding cases where it is already a function

I am working on a JavaScript function and I want to define a type signature for it.

function wrapInFunction(value) {
  if (typeof value === 'function') {
    return value;
  } else {
    return () => value;
  }
}

This function takes an input that may or may not be a function. If the input is not a function, it transforms it into one in a simple manner. Initially, I attempted to do this:

function wrapInFunction<A extends Array<unknown>, B>(value: B | ((...a: A) => B)): (...a: A) => B {
  if (typeof value === 'function') {
    return value;
  } else {
    return () => value;
  }
}

However, TypeScript flagged an issue where B & Function might cause a type error if nonempty in the first case.

src/op.ts:360:5 - error TS2322: Type '((...a: A) => B) | (B & Function)' is not assignable to type '(...a: A) => B'.
  Type 'B & Function' is not assignable to type '(...a: A) => B'.
    Type 'Function' provides no match for the signature '(...a: A): B'.

360     return value;

To address this concern, I attempted to use the Exclude utility

function wrapInFunction<A extends Array<unknown>, B>(value: Exclude<B, Function> | ((...a: A) => B)): (...a: A) => B {
  if (typeof value === 'function') {
    return value;
  } else {
    return () => value;
  }
}

Despite this adjustment, the error persisted:

src/op.ts:360:5 - error TS2322: Type '((...a: A) => B) | (Exclude<B, Function> & Function)' is not assignable to type '(...a: A) => B'.
  Type 'Exclude<B, Function> & Function' is not assignable to type '(...a: A) => B'.
    Type 'Function' provides no match for the signature '(...a: A): B'.

360     return value;

In my understanding,

Exclude<B, Function> & Function
should result in an empty type. If I can demonstrate to TypeScript that this scenario is impossible, then the type signature should work properly.

Is there a way to prove that

Exclude<B, Function> & Function
is always empty? Or perhaps, is there a better approach to defining the type signature for my wrapInFunction function?

Side Note: When calling this function within my program, I will be using instances of B that are clearly not functions, such as class types and primitives like number. Therefore, for my current use cases, Exclude<B, Function> and B should have identical members. However, it would be beneficial to demonstrate this to the type checker without relying on manual casting with value as (...a: A) => B.

Answer №1

Are you satisfied with the results?

type T<C> = C extends Function? C : () => C ;

function convertToFunction<C>(item: C): T<C> {
  return (typeof item === 'function'? item : () => item) as T<C>;
}

convertToFunction(456);

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