Encountering an error stating "Potential null object" while attempting to retrieve the total count of characters and numbers in a given string

Currently, I am trying to find the number of characters and digits that repeat more than once in a given input string.

For example, if the input is "zzrrcde", the output should be 2 as both z and r occur more than once.

Here is the function I have written after conducting some research. Instead of using nested loops, I opted for regex. However, I am encountering an error: TS2531 Object is possibly null. Can someone clarify why this error is happening? The error seems to point to the use of text in the return statement.

export function duplicateCount(text: string): number {
  try{ return text.toLowerCase().split("").sort().join("").match(/(.)\1+/g).length; }
  catch(e){ return 0; }
}

console.log(duplicateCount("aabbcde"))

I attempted a different approach by declaring a new variable var newText = text, but unfortunately, I still face the same error.

export function duplicateCount(text: string): number{
  var newText = text;
  try{ return newText.toLowerCase().split("").sort().join("").match(/(.)\1+/g).length; }
  catch(e){ return 0; }
}

console.log(duplicateCount("aabbcde"))

Could someone please guide me on what could be causing this issue? I am new to TypeScript, so any detailed explanation would be very helpful.

Answer №1

When a universal regex fails to find a match in the string, it won't return an empty array but rather null. Consider this scenario using your own code:

function countDuplicates(text) {
  return text.toLowerCase().split("").sort().join("").match(/(.)\1+/g).length;
}

console.log(countDuplicates("xyz"));

Avoid relying on try/catch for routine expected control flow, particularly in TypeScript - verify if a match exists before proceeding. Save error handling for unpredictable situations such as failures in asynchronous APIs.

const match = text.toLowerCase().split("").sort().join("").match(/(.)\1+/g);
return match ? match.length : 0;

To enhance efficiency, you could eliminate the need for .sort (O(n log n)) and instead iterate through each character individually:

export function countDuplicates(text: string) {
    const charCount: { [char: string]: number } = {};
    for (const char of text) {
        charCount[char] = (charCount[char] || 0) + 1;
    }
    return Object.values(charCount)
        .filter(val => val >= 2)
        .length;
}

Answer №2

If your match turns out to be null, you have the option to include a default value.

export function countDuplicateCharacters(text: string): number {
  try {
    return text.toLowerCase().split("").sort().join("").match(/(.)\1+/g)?.length || 0;
  }
  catch (e) {
    return 0;
  }
}

console.log(countDuplicateCharacters("aabbcde"))

Answer №3

Is the utilization of the try statement really necessary?

function findDuplicateChars(text) {
  if (!text) return 0;
  let matchedArray = text.toLowerCase().split("").sort().join("").match(/(.)\1+/g);
  return matchedArray ? matchedArray.length : 0;
}

console.log(findDuplicateChars("aabbcde"))
console.log(findDuplicateChars("abcdee"))
console.log(findDuplicateChars(""))

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