Enhance your Typescript code with a type guard that supports optional wrapped types

I haven't come across a question similar to this one before. My goal is to develop a type guard that can accurately determine the type of a specific variable. It's quite simple with a single type.

type A = { id: number, title: string, type: string };
type B = { id: number, title: string, type: string };
type ABUnion = A | B;

const isA = (value: ABUnion): value is A => value.type === 'A';

However, in certain scenarios, I encounter these types encapsulated within another type and aim to preserve the wrapper type while ensuring that the inner type matches my requirement.

type A = { id: number, title: string, type: string };
type B = { id: number, title: string, type: string };
type ABUnion = A | B | Readonly<A> | Readonly<B>;

const isA = (value: ABUnion): value is A => value.type === 'A';

In this situation, regardless of passing a Readonly<A> into the guard, I consistently receive a typeof A, which is as anticipated.

How can I modify isA to output either A or Readonly<A> (or a different wrapped type)?

Answer №1

After a brief moment of reflection, it became clear that the solution was right in front of me.

const isA = <T>(value: T): value is T => value.type === 'A';

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