I'm working with an interface that looks like this
interface Cat {
color: string,
weight: number,
cute: Boolean, // even though all cats are cute!
}
Currently, I need to accomplish something similar to this
const kitten: Cat = ...
Object.keys(kitten).some(prop => ['weight', 'color'].includes(prop)
Is there a method to ensure that the strings provided in the array (['weight', 'color']) are part of the interface Cat?
let keys: (keyof Cat)[] = ['weight', 'color'];
Object.keys(kitten).some(prop => keys.includes(prop))
or for typescript version 4.9 or above
Object.keys(kitten).some(prop => (['weight', 'color'] satisfies (keyof Cat)[]).includes(prop))
to get around the error with Object.keys.
type ObjectKeys<T> = (keyof T)[];
(Object.keys(kitten) as ObjectKeys<Cat>).some(prop => (['weight', 'color'] satisfies (keyof Cat)[]).includes(prop))
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