Error encountered during Typescript compilation: Type 'void' cannot be assigned to type 'Item[]'

Below are my typescript functions. When I edit in vscode, the second function does not show any error message. However, upon compilation, an error is displayed for the second function:

error TS2322: Type 'Promise<void>' is not assignable to type 'Promise<Item[]>'.
      Type 'void' is not assignable to type 'Item[]'.

The error disappears when I remove .catch(...). Can someone please assist me?

// Function to retrieve a single item.
// Q is https://github.com/kriskowal/q
function getItem(id: number): Q.Promise<Item> {
    const deferred = Q.defer<Item>();
    // Asynchronous process.
    return deferred.promise;
}

// Function to retrieve a batch of items.
function getItems(ids: number[]): Q.Promise<Item[]> {
   return Q.all(ids.map(id => {
       return getSingleItem(id);
   })).then(results => {
      let items = [];
      results.forEach(result => {
          items = items.concat(result);
      });
      return items;
   }).catch(error => {
       throw error;
   });
}

Answer №1

While this answer may not be perfect, it does get the job done with a couple of workarounds. 1. Instead of returning Q.Promise<any>, which is not recommended. 2. Error can be wrapped in a deferred.reject(error) as shown below:

// Function to retrieve a batch of items.
function getItems(ids: number[]): Q.Promise<Item[]> {
   const deferred = Q.defer<Item[]>();
   return Q.all(ids.map(id => {
       return getSingleItem(id);
   })).then(results => {
      let items = [];
      results.forEach(result => {
          items = items.concat(result);
      });
      deferred.resolve(items);
   }).catch(error => {
      deferred.reject(error); // Error wrapped in defer.
   });
   return deferred.promise;
}

Although not an ideal solution, it can temporarily help those in need of a quick fix.

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